According to the Hardy-Weinberg's equation `p^2 + q^2 + 2pq` is equal to-

Options

A. 1
B. 2
C. 0
D. 3

Answer

To solve the question regarding the Hardy-Weinberg equation, we will break it down step by step.

### Step-by-Step Solution:

1. **Understanding the Hardy-Weinberg Principle**:
The Hardy-Weinberg principle is a fundamental concept in population genetics that describes how allele frequencies in a population remain constant from generation to generation in the absence of evolutionary influences.

2. **The Hardy-Weinberg Equation**:
The equation is represented as:
\[ p^2 + 2pq + q^2 = 1 \]
where:
- \( p \) represents the frequency of the dominant allele.
- \( q \) represents the frequency of the recessive allele.

3. **Components of the Equation**:
- \( p^2 \) is the frequency of the homozygous dominant genotype.
- \( 2pq \) is the frequency of the heterozygous genotype.
- \( q^2 \) is the frequency of the homozygous recessive genotype.

4. **Total Frequency**:
The sum of the frequencies of all genotypes in a population must equal 1, which is a fundamental principle of probability. Therefore:
\[ p^2 + 2pq + q^2 = 1 \]

5. **Conclusion**:
Thus, according to the Hardy-Weinberg equation, \( p^2 + q^2 + 2pq \) is equal to 1.

### Final Answer:
According to the Hardy-Weinberg equation, \( p^2 + q^2 + 2pq = 1 \).

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