Home
Class 12
PHYSICS
The voltage of clouds is 4xx10^(6) v wit...

The voltage of clouds is `4xx10^(6)` v with respect V with respect to ground . In a lightning strike lasting 100 ms a charge of 4 C is delivered to the ground . The power of lightning strike is

A

160MW

B

80MW

C

20MW

D

500KW

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Similar Questions

Explore conceptually related problems

The voltage of clouds is 4 xx 10 ^( 6 ) volt with respect to ground. In a a lightening strike lasting 100 sec, a charge of 4 coulomb is delivered to the ground. The power of lightening strike is

The voltage of clouds is 4 xx 10^(6) V with respect to ground. In a lighting strike lasting 100 ms , a charge of 4 C is delivered to the ground. The power of ligthing strike is

What is lightning (b) How do the clouds get electrically charged ? (c) How does lightning strike a building ?

A cloud is at a potential of 8 xx 10^(6) volt relative to the ground. A charge of 80 coulomd is transferred in lightening stroke betwee the cloud and the gorund. Assuming the potential of the cloud of remain constant, the energy dissipated is

A ring rolls without slipping on the ground. Its centre C moves with a constant speed u.P is any point on the ring. The speed of P with respect to the ground is v .

An elevator without a ceiling is ascending up with an acceleration of 5 ms^-2. A boy on the elevator shoots a ball in vertical upward direction from a height of 2 m above the floor of elevator. At this instant the elevator is moving up with a velocity of 10 ms^-1 and floor of the elevator is at a height of 50 m from the ground. The initial speed of the ball is 15 ms^-1 with respect to the elevator. Consider the duration for which the ball strikes the floor of elevator in answering following questions. ( g=10 ms^-2 ) 3. Displacement of ball with respect to ground during its night would be

An elevator without a ceiling is ascending up with an acceleration of 5 ms^-2. A boy on the elevator shoots a ball in vertical upward direction from a height of 2 m above the floor of elevator. At this instant the elevator is moving up with a velocity of 10 ms^-1 and floor of the elevator is at a height of 50 m from the ground. The initial speed of the ball is 15 ms^-1 with respect to the elevator. Consider the duration for which the ball strikes the floor of elevator in answering following questions. ( g=10 ms^-2 ) 2. The maximum height reached by ball, as measured from the ground would be

A ball of mass 10 g falls from a height of y 5 m. It rebounds from the ground to a height of 4m. Find : (a) the initial potential energy of the ball, (b) the kinetic energy of the ball just before the ground. striking the ground, (c) the kinetic energy of the ball after striking the ground ,and (d) the loss in kinetic energy on striking the ground . Take g=9.8 m s^(-2) .

A ball is projected with a speed of 2ms^(-1) with respect to a trolley which is moving with 4ms^(-1) , as shown in the figure. The angle at which ball is projected with respect to the horizontal in ground frame is

An elevator without a ceiling is ascending up with an acceleration of 5 ms^-2. A boy on the elevator shoots a ball in vertical upward direction from a height of 2 m above the floor of elevator. At this instant the elevator is moving up with a velocity of 10 ms^-1 and floor of the elevator is at a height of 50 m from the ground. The initial speed of the ball is 15 ms^-1 with respect to the elevator. Consider the duration for which the ball strikes the floor of elevator in answering following questions. ( g=10 ms^-2 ) 1. The time in which the ball strikes the floor of elevator is given by