Hydroboration oxidation and acid hydration will yield the same product in case of:

Options

A.
B.
C. `CH_(2) = CH_(2)`
D. `CH_(3)CH= CH-CH_(3)`

Answer

To determine which reaction conditions yield the same product from hydroboration-oxidation and acid hydration, we need to analyze the nature of the alkenes involved. Here's a step-by-step breakdown of the solution:

### Step 1: Understand Acid Hydration
- Acid hydration involves the addition of water (H₂O) to an alkene in the presence of an acid (H⁺).
- For symmetrical alkenes, this reaction yields a single product (an alcohol) since both sides of the double bond are identical.
- For unsymmetrical alkenes, the reaction follows Markovnikov's rule, where the hydroxyl group (OH) attaches to the carbon with the greater number of hydrogen atoms.

### Step 2: Understand Hydroboration-Oxidation
- Hydroboration-oxidation involves the addition of borane (BH₃) to the alkene, followed by oxidation with hydrogen peroxide (H₂O₂) in a basic medium.
- For symmetrical alkenes, this also yields a single product (an alcohol).
- For unsymmetrical alkenes, this reaction follows the anti-Markovnikov rule, where the hydroxyl group attaches to the less substituted carbon.

### Step 3: Identify Symmetrical Alkenes
- To ensure that both reactions yield the same product, we need to identify symmetrical alkenes.
- Symmetrical alkenes will produce the same alcohol regardless of whether hydroboration-oxidation or acid hydration is used.

### Step 4: Analyze the Given Options
- **Option A:** Unsymmetrical alkene (not symmetrical).
- **Option B:** Symmetrical alkene (both sides are identical).
- **Option C:** Symmetrical alkene (both sides are identical).
- **Option D:** Symmetrical alkene (both sides are identical).

### Step 5: Conclusion
- The correct answer is that options B, C, and D are symmetrical alkenes, which will yield the same product from both hydroboration-oxidation and acid hydration.

### Final Answer
The correct options that yield the same product in both reactions are **B, C, and D**.

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