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The energy of a photon is equal to the k...

The energy of a photon is equal to the kinetic energy of a
proton. The energy of the photon is E. Let `lambda_1`be the de-Broglie wavelength of the
proton and `lambda_2` be the wavelength of the photon. The ratio `(lambda_1)/(lambda_2)` is proportional to
(a)`E^0` (b) `E^(1//2)` (c ) `E^(-1)` (d)`E^(-2)`

A

`E^0`

B

`E^(1//2)`

C

`E^(-1)`

D

`E^(-2)`

Text Solution

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The correct Answer is:
B
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