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How many groups are ortho/para director ...

How many groups are ortho/para director in the electrophillic aromatic substitution?
(i) `-NH_(2) (ii) -COH (iii) -N=O (iv) -COOH`
`(v) -Et (vi) -N = NH_(2) (vii) -SO_(3)H`
(viii) `-O-underset(O)underset(||)(C)-Ome (ix)`
`-overset(O)overset(||)(C) - NH - Me`

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The correct Answer is:
To determine how many groups are ortho/para directors in electrophilic aromatic substitution, we need to analyze each substituent based on its ability to donate or withdraw electrons from the benzene ring. Ortho/para directing groups are typically electron-donating groups that increase the electron density at the ortho and para positions of the aromatic ring. Let's evaluate each substituent step by step: 1. **-NH₂ (Amino Group)**: - The nitrogen atom has a lone pair that can donate electrons to the benzene ring. - **Conclusion**: This group is an ortho/para director. 2. **-CHO (Aldehyde Group)**: - The carbonyl group (C=O) is electron-withdrawing due to the electronegativity of oxygen. - **Conclusion**: This group is a meta director, not ortho/para. 3. **-N=O (Nitro Group)**: - The nitro group is also electron-withdrawing due to the presence of the highly electronegative oxygen. - **Conclusion**: This group is a meta director, not ortho/para. 4. **-COOH (Carboxylic Acid Group)**: - Similar to the aldehyde, the carboxylic acid group has a carbonyl that withdraws electrons. - **Conclusion**: This group is a meta director, not ortho/para. 5. **-Et (Ethyl Group)**: - The ethyl group is an alkyl group that can donate electrons through hyperconjugation. - **Conclusion**: This group is an ortho/para director. 6. **-N=NH₂ (Hydrazine Group)**: - The nitrogen has a lone pair that can donate electrons to the benzene ring. - **Conclusion**: This group is an ortho/para director. 7. **-SO₃H (Sulfonic Acid Group)**: - The sulfonic acid group is electron-withdrawing due to the presence of the highly electronegative oxygen atoms. - **Conclusion**: This group is a meta director, not ortho/para. 8. **-O=C-OCH₃ (Acetoxy Group)**: - The carbonyl (C=O) is electron-withdrawing, but the methoxy (OCH₃) part can donate electrons. - However, the overall effect is that it behaves as a meta director due to the carbonyl. - **Conclusion**: This group is a meta director, not ortho/para. 9. **-O=C-NH-Me (Amide Group)**: - The carbonyl group is electron-withdrawing, and the nitrogen does not sufficiently donate electrons to overcome this effect. - **Conclusion**: This group is a meta director, not ortho/para. Now, let's summarize the findings: - Ortho/para directors: **-NH₂, -Et, -N=NH₂** - Meta directors: **-CHO, -N=O, -COOH, -SO₃H, -O=C-OCH₃, -O=C-NH-Me** **Total ortho/para directing groups = 3**
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