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RH(2) (ion exchange resin) can replace C...

`RH_(2)` (ion exchange resin) can replace `Ca^(2+)` ions in hard water as `RH_(2)+Ca^(2+) to RCa+2H^(+)`. If L of hard water after passing through `RH_(2)` has pH=3 then hardness in parts per million of `Ca^(2+)` is :

A

10 ppm

B

40 ppm

C

100 ppm

D

20 ppm

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The correct Answer is:
D
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RH_2 (ion exchange resin) can replace Ca^(2+) ions in hard water as RH_2+Ca^(2+)rarr RCa+2H^+ . If 1 L of hard water after passing through RH_2 has pH=3 then hardness in parts per million of Ca^(2+) is :

RH_(2) ( ion exchange resin) can replace Ca^(2+) d in hard water as. RH_(2)+Ca^(2+)rarrRCa+2H^(+) 1 "litre" of hard water passing through RH_(2) has pH2 . Hence hardness in pp m "of" Ca^(2+) is:

Ca+H_2O to

10 L of hard water required 0.56 g of lime (CaO) for removing hardness. Hence, temporary hardness in ppm (part per million 10^(6) ) of CaCO_(3) is:

In reference to biological role, Ca^(2+) ions are important in

Name the compound used for measuring the hardness of water, i.e., for estimation of Ca^(2+) and Mg^(2+) ions.

Ca(OH)_(2) removes temporary hardness by forming

A : Temporary hardness is due to HCO_(3)^(-) ions. R : permanent hardness is due to CaCl_(2)

A water is said to be soft water if it produces sufficient foam with the soap and water that does not produce foam with soap is known as hard water. Hardness has been classified into two types (i)Temporary hardness (ii) Permanent hardness. Temporary hardness is due to presence of calcium and magnesium bicarbonate. It is simply removed by boiling as Ca(HCO_(3))_(2)overset(Delta)rarr CaCO_(3)darr+CO_(2)uarr+H_(2)O Mg(HCO_(3))_(2)overset(Delta)rarr MgCO_(3)darr+CO_(2)uarr+H_(2)O temporary hardness can also be removed by addition of slaked lime, Ca(OH)_(2) Ca(HCO_(3))_(2)+Ca(OH)_(2)to2CaCO_(3)darr+2H_(2)O permanent hardsness is due to presencce of sulphates and chlorides of Ca,Mg,etc. It is removed by washing soda as CaCl_(2)+Na_(2)CO_(3)toCaCO_(3)darr+2NaCl CaSO(4)+Na_(2)CO_(3)to CaCO_(3)darr+Na_(2)SO_(4) Permanent hardness also removed by ion exchange resin process as 2RH+Ca^(2+) to R_(2)Ca+2H^(+) 2ROH+SO_(4)^(2-)toR_(2)SO_(4)+2OH^(-) The degree of hardness of water is measured in terms of PPm of CaCO_(3) 100 PPm means 100 g of CaCO_(3) is present in 10^(6) g of H_(2)O . If any other water sample which contain 120 PPm of MgSO_(4) , hardness in terms of CaCO_(3) is equal to =100 PPm. What is the mass of Ca(OH)_(2) required for 10 litre of water remove temporary hardness of 100 PPm due to Ca(HCO_(3))_(2) ?

A water is said to be soft water if it produces sufficient foam with the soap and water that does not produce foam with soap is known as hard water. Hardness has been classified into two types (i)Temporary hardness (ii) Permanent hardness. Temporary hardness is due to presence of calcium and magnesium bicarbonate. It is simply removed by boiling as Ca(HCO_(3))_(2)overset(Delta)rarr CaCO_(3)darr+CO_(2)uarr+H_(2)O Mg(HCO_(3))_(2)overset(Delta)rarr MgCO_(3)darr+CO_(2)uarr+H_(2)O temporary hardness can also be removed by addition of slaked lime, Ca(OH)_(2) Ca(HCO_(3))_(2)+Ca(OH)_(2) to 2CaCO_(3)darr+2H_(2)O permanent hardsness is due to presencce of sulphates and chlorides of Ca,Mg,etc. It is removed by washing soda as CaCl_(2)+Na_(2)CO_(3) to CaCO_(3)darr+2NaCl CaSO(4)+Na_(2)CO_(3)to CaCO_(3)darr+Na_(2)SO_(4) Permanent hardness also removed by ion exchange resin process as 2RH+Ca^(2+)toR_(2)Ca+2H^(+) 2ROH+SO_(4)^(2-) to R_(2)SO_(4)+2OH^(-) The degree of hardness of water is measured in terms of PPm of CaCO_(3) 100 PPm means 100 g of CaCO_(3) is present in 10^(6) g of H_(2)O . If any other water sample which contain 120 PPm of MgSO_(4) , hardness in terms of CaCO_(3) is equal to =100 PPm. One litre of a sample of hard water (d=1 g/mL) cotains 136 mg of CaSO_(4) and 190 mg of MgCl_(2) . What is the total hardness of water in terms of CaCO_(3) ?