If asin^2x+bcos^2x=c,bsin^2y+acos^2y=d,a...

If `asin^2x+bcos^2x=c,bsin^2y+acos^2y=d,and atanx=btany`, then prove that `a^2/b^2=((d-a)(c-a))/((b-c)(b-d))`.

A

`((b-c)(d-b))/((a-d)(a-b))`

B

`((a-d)(c-a))/((b-c)(d-b))`

C

`((d-a)(c-a))/((b-c)(d-b))`

D

`((b-c)(b-d))/((a-c)(a-d))`

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The correct Answer is:

B

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