`XeF_6` on partial hydrolysis with water produces a compound ‘X’. The same compound ‘X’ is formed when `XeF_6` reacts with silica. The compound ‘X’ Is:

Options

A. `XeF_(4)`
B. `XeF_(2)`
C. `XeO_(3)`
D. `XeOF_(4)`

Answer

To solve the question, we will analyze the reactions involving \( \text{XeF}_6 \) and determine the compound \( X \) formed during these reactions.

### Step-by-Step Solution:

1. **Understanding the Reaction with Water:**
- When \( \text{XeF}_6 \) undergoes partial hydrolysis with water, it reacts to form \( \text{XeOF}_4 \) and \( \text{HF} \).
- The reaction can be represented as:
\[ \text{XeF}_6 + \text{H}_2\text{O} \rightarrow \text{XeOF}_4 + 2\text{HF} \]
- Here, \( \text{XeOF}_4 \) is the product formed, which we will refer to as compound \( X \).

2. **Understanding the Reaction with Silica:**
- Next, we consider the reaction of \( \text{XeF}_6 \) with silica, which is \( \text{SiO}_2 \).
- The reaction can be represented as:
\[ \text{XeF}_6 + \text{SiO}_2 \rightarrow \text{XeOF}_4 + \text{SiF}_4 \]
- Again, \( \text{XeOF}_4 \) is produced in this reaction, confirming that \( X \) is indeed \( \text{XeOF}_4 \).

3. **Conclusion:**
- Since both reactions yield the same compound \( X \), we conclude that the compound \( X \) is \( \text{XeOF}_4 \).

### Final Answer:
The compound \( X \) is \( \text{XeOF}_4 \).

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