At room temperature copper has free electron density of `8.4xx10^(28) per m^(3)` . The copper conductor has a cross-section of `10^(-6)m^(2)` and carries a current of 5.4 A. What is the electron drift velocity in copper?
At room temperature copper has free electron density of `8.4xx10^(28) per m^(3)` . The copper conductor has a cross-section of `10^(-6)m^(2)` and carries a current of 5.4 A. What is the electron drift velocity in copper?
A
`4ms^(-1)`
B
`0.4ms^(-1)`
C
`"4 cm s"^(-1)`
D
`"0.4 mm s"^(-1)`
Text Solution
AI Generated Solution
The correct Answer is:
To find the electron drift velocity in copper, we can use the relationship between current (I), electron density (N), charge of an electron (E), cross-sectional area (A), and drift velocity (V_d). The formula we will use is:
\[ I = N \cdot A \cdot e \cdot V_d \]
Where:
- \( I \) = Current (in Amperes)
- \( N \) = Free electron density (in electrons per cubic meter)
- \( A \) = Cross-sectional area (in square meters)
- \( e \) = Charge of an electron (approximately \( 1.6 \times 10^{-19} \) Coulombs)
- \( V_d \) = Drift velocity (in meters per second)
### Step-by-step Solution:
1. **Identify the given values:**
- Free electron density, \( N = 8.4 \times 10^{28} \, \text{m}^{-3} \)
- Cross-sectional area, \( A = 10^{-6} \, \text{m}^{2} \)
- Current, \( I = 5.4 \, \text{A} \)
- Charge of an electron, \( e = 1.6 \times 10^{-19} \, \text{C} \)
2. **Rearrange the formula to solve for drift velocity \( V_d \):**
\[
V_d = \frac{I}{N \cdot A \cdot e}
\]
3. **Substitute the known values into the equation:**
\[
V_d = \frac{5.4}{(8.4 \times 10^{28}) \cdot (10^{-6}) \cdot (1.6 \times 10^{-19})}
\]
4. **Calculate the denominator:**
- First, calculate \( N \cdot A \cdot e \):
\[
N \cdot A \cdot e = (8.4 \times 10^{28}) \cdot (10^{-6}) \cdot (1.6 \times 10^{-19})
\]
- Calculate \( 8.4 \times 1.6 = 13.44 \)
- Now, \( 13.44 \times 10^{28 - 6 - 19} = 13.44 \times 10^{3} = 1.344 \times 10^{4} \)
5. **Now substitute back into the drift velocity equation:**
\[
V_d = \frac{5.4}{1.344 \times 10^{4}} \approx 4.007 \times 10^{-4} \, \text{m/s}
\]
6. **Convert the drift velocity to centimeters per second:**
\[
V_d \approx 4.007 \times 10^{-4} \, \text{m/s} = 0.04007 \, \text{cm/s} \approx 0.04 \, \text{cm/s}
\]
7. **Final answer:**
\[
V_d \approx 0.4 \, \text{mm/s}
\]
### Final Result:
The electron drift velocity in copper is approximately \( 4 \times 10^{-4} \, \text{m/s} \) or \( 0.04 \, \text{cm/s} \) or \( 0.4 \, \text{mm/s} \).
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In a metal in the solid state, such as a copper wire, the atoms are strongly bound to one another and occupý fixed positions. Some electrons (called the conductor electrons) are free to move in the body of the metal while the other are strongly bound to their atoms. In good conductors, the number of free electrons is very large of the order of 10^(28) electrons per cubic metre in copper. The free electrons are in random motion and keep colliding with atoms. At room temperature, they move with velocities of the order of 10^5 m/s. These velocities are completely random and there is not net flow of charge in any directions. If a potential difference is maintained between the ends of the metal wire (by connecting it across a battery), an electric field is set up which accelerates the free electrons: These accelerated electrons frequently collide with the atoms of the conductor, as a result, they acquire a constant speed called the drift speed which is given by V_e = 1/enA where I = current in the conductor due to drifting electrons, e = charge of electron, n = number of free electrons per unit volume of the conductor and A = area of cross-section of the conductor. A uniform wire of length 2.0 m and cross-sectional area 10^(-7) m^(2) carries a current of 1.6 A. If there are 10^(28) free electrons per m in copper, the drift speed of electrons in copper is
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Estimate the average drift speed of conduction electrons in a copper wire of cross-sectional area 2.0 xx 10^(-7)m^(2) carrying a current of 3.0 A. Assume that each copper atom contributes roughly one conduction electron. The density of copper is 9.0 xx10^(3) kg//m^(3) , and its atomic mass is 63.5 u.
In a metal in the solid state, such as a copper wire, the atoms are strongly bound to one another and occupý fixed positions. Some electrons (called the conductor electrons) are free to move in the body of the metal while the other are strongly bound to their atoms. In good conductors, the number of free electrons is very large of the order of 10^(28) electrons per cubic metre in copper. The free electrons are in random motion and keep colliding with atoms. At room temperature, they move with velocities of the order of 10^5 m/s. These velocities are completely random and there is not net flow of charge in any directions. If a potential difference is maintained between the ends of the metal wire (by connecting it across a battery), an electric field is set up which accelerates the free electrons: These accelerated electrons frequently collide with the atoms of the conductor, as a result, they acquire a constant speed called the drift speed which is given by V_e = 1/enA where I = current in the conductor due to drifting electrons, e = charge of electron, n = number of free electrons per unit volume of the conductor and A = area of cross-section of the conductor. A current of 1 A flows through a copper wire. The number of electrons passing through any cross-section of the wire in 1.6 sec is (charge of a electron = 1.6 xx 10^(-19 c) .
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