The final product formed when methylamine is treated with `NaNO_(2)` and HCl followed by hydrolysis is :

Options

A. Nitromethane
B. Methylcyanide
C. Methyl alcohol
D. Diazomethane

Answer

To solve the question regarding the final product formed when methylamine is treated with NaNO₂ and HCl followed by hydrolysis, let's break down the steps involved in the reaction:

### Step 1: Identify the Reactants
The reactants in this reaction are:
- Methylamine (CH₃NH₂)
- Sodium nitrite (NaNO₂)
- Hydrochloric acid (HCl)

### Step 2: Formation of Nitrous Acid
When sodium nitrite (NaNO₂) is mixed with hydrochloric acid (HCl), nitrous acid (HNO₂) is formed:
\[ \text{NaNO}_2 + \text{HCl} \rightarrow \text{HNO}_2 + \text{NaCl} \]

### Step 3: Reaction of Methylamine with Nitrous Acid
Methylamine (CH₃NH₂) reacts with nitrous acid (HNO₂) to form diazomethane (CH₃N₂⁺). This reaction can be represented as:
\[ \text{CH}_3\text{NH}_2 + \text{HNO}_2 \rightarrow \text{CH}_3\text{N}_2^+ + \text{H}_2\text{O} \]
Here, diazomethane is highly unstable and will decompose.

### Step 4: Decomposition of Diazomethane
The unstable diazomethane (CH₃N₂⁺) decomposes, releasing nitrogen gas (N₂) and forming a methyl cation (CH₃⁺):
\[ \text{CH}_3\text{N}_2^+ \rightarrow \text{CH}_3^+ + \text{N}_2 \]

### Step 5: Hydrolysis of Methyl Cation
The methyl cation (CH₃⁺) can then react with water (H₂O) during hydrolysis. The water molecule provides hydroxide ions (OH⁻) and protons (H⁺), leading to the formation of methanol (CH₃OH):
\[ \text{CH}_3^+ + \text{H}_2\text{O} \rightarrow \text{CH}_3\text{OH} + \text{H}^+ \]

### Final Product
Thus, the final product formed after treating methylamine with NaNO₂ and HCl followed by hydrolysis is:
**Methanol (CH₃OH)**

### Conclusion
The answer to the question is that the final product is methyl alcohol (methanol).

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