In an organism, if the normal diploid number of chromosmes is 8, how many chromatids are present in each daughter cell at the end of meiosis I

Options

A. 2
B. 4
C. 8
D. 16

Answer

To solve the question regarding the number of chromatids present in each daughter cell at the end of meiosis I when the normal diploid number of chromosomes is 8, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Diploid Number**:
The diploid number of chromosomes in the organism is given as 8. This means that in a somatic (body) cell, there are 8 chromosomes.

2. **Understand Meiosis**:
Meiosis consists of two rounds of cell division: meiosis I and meiosis II. At the end of meiosis I, the diploid cell divides into two haploid cells.

3. **Calculate the Number of Chromosomes After Meiosis I**:
Since meiosis I reduces the chromosome number by half, each daughter cell will have half of the original diploid number.
\[ \text{Number of chromosomes in each daughter cell} = \frac{8}{2} = 4 \]

4. **Determine the Number of Chromatids**:
Each chromosome is made up of two sister chromatids. Therefore, if there are 4 chromosomes in each daughter cell, we can calculate the total number of chromatids in each daughter cell.
\[ \text{Number of chromatids in each daughter cell} = 4 \text{ chromosomes} \times 2 \text{ chromatids/chromosome} = 8 \text{ chromatids} \]

5. **Conclusion**:
At the end of meiosis I, each daughter cell will contain 8 chromatids.

### Final Answer:
At the end of meiosis I, each daughter cell will have **8 chromatids**.

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