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A metal ball falls from a height of 1m o...

A metal ball falls from a height of 1m on to a steel plate and jumps upto a height of 81 cm. The coefficient of restitution of the ball and steel plate is

A

0.2

B

9

C

0.9

D

90

Text Solution

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The correct Answer is:
To find the coefficient of restitution (e) between the metal ball and the steel plate, we can follow these steps: ### Step 1: Understand the Problem The metal ball falls from a height of 1 meter (h1) and bounces back to a height of 81 cm (h2). We need to find the coefficient of restitution, which is defined as the ratio of the velocity of separation to the velocity of approach. ### Step 2: Use the Formula for Velocity The velocity of the ball just before it hits the steel plate (v1) can be calculated using the formula for free fall: \[ v_1 = \sqrt{2gh_1} \] Where: - \( g \) is the acceleration due to gravity (approximately \( 9.81 \, \text{m/s}^2 \)) - \( h_1 = 1 \, \text{m} \) ### Step 3: Calculate v1 Substituting the values: \[ v_1 = \sqrt{2 \cdot 9.81 \cdot 1} \] \[ v_1 = \sqrt{19.62} \] \[ v_1 \approx 4.43 \, \text{m/s} \] ### Step 4: Calculate the Velocity After the Bounce The velocity of the ball just after it bounces back to a height of 81 cm (h2) can be calculated using the same formula: \[ v_2 = \sqrt{2gh_2} \] Where: - \( h_2 = 81 \, \text{cm} = 0.81 \, \text{m} \) ### Step 5: Calculate v2 Substituting the values: \[ v_2 = \sqrt{2 \cdot 9.81 \cdot 0.81} \] \[ v_2 = \sqrt{15.8762} \] \[ v_2 \approx 3.98 \, \text{m/s} \] ### Step 6: Find the Coefficient of Restitution The coefficient of restitution (e) is given by: \[ e = \frac{v_2}{v_1} \] ### Step 7: Substitute the Values Substituting the calculated values: \[ e = \frac{3.98}{4.43} \] \[ e \approx 0.9 \] ### Final Answer The coefficient of restitution of the ball and steel plate is approximately **0.9**. ---
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