The total number possible isomers for the complex compound `[Cu(NH_(3))_(4) [PtCI_(4)]` are

Options

A. 4
B. 5
C. 6
D. 3

Answer

To determine the total number of possible isomers for the complex compound \([Cu(NH_3)_4][PtCl_4]\), we will analyze the types of isomerism that can occur in this compound.

### Step 1: Identify the Components
The complex consists of two metal centers: copper (Cu) and platinum (Pt). Copper is coordinated with four ammonia (NH₃) ligands, while platinum is coordinated with four chloride (Cl) ligands.

### Step 2: Understand Coordination Isomerism
Coordination isomerism occurs when the ligands associated with the metal centers can be exchanged. In this case, we can exchange some of the ammonia ligands with chloride ligands.

### Step 3: List Possible Isomers
1. **First Isomer**: \([Cu(NH_3)_4][PtCl_4]\) - The original complex.
2. **Second Isomer**: \([Cu(NH_3)_3Cl][PtCl_3(NH_3)]\) - One ammonia is replaced by one chloride.
3. **Third Isomer**: \([Cu(NH_3)_2Cl_2][PtCl_2(NH_3)_2]\) - Two ammonia ligands are replaced by two chlorides.
4. **Fourth Isomer**: \([Cu(NH_3)Cl_3][PtCl(NH_3)_3]\) - Three ammonia ligands are replaced by three chlorides.
5. **Fifth Isomer**: \([CuCl_4][Pt(NH_3)_4]\) - All ammonia ligands are replaced by chlorides.

### Step 4: Count the Isomers
From the above analysis, we have identified five distinct coordination isomers based on the exchange of ligands between the copper and platinum centers.

### Conclusion
The total number of possible isomers for the complex \([Cu(NH_3)_4][PtCl_4]\) is **5**.

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