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A laser light of wavelength 660 nm is us...

A laser light of wavelength 660 nm is used to weld Retina detachment. If a laser pulse of width 60 ms and power 0.5 kW is used, the approximate number of photons in the pulse are (Take Planck's Constant, `h=6.62xx10^(-34)Js`)

A

`10^(22)`

B

`10^(19)`

C

`10^(20)`

D

`10^(18)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the approximate number of photons in a laser pulse using the given parameters. Let's break it down step by step. ### Step 1: Understand the given parameters - Wavelength of laser light, \( \lambda = 660 \, \text{nm} = 660 \times 10^{-9} \, \text{m} \) - Power of the laser, \( P = 0.5 \, \text{kW} = 500 \, \text{W} \) - Width of the pulse, \( T = 60 \, \text{ms} = 60 \times 10^{-3} \, \text{s} \) - Planck's constant, \( h = 6.62 \times 10^{-34} \, \text{Js} \) - Speed of light, \( c = 3 \times 10^8 \, \text{m/s} \) ### Step 2: Use the formula to find the number of photons The relationship between power, energy per photon, and the number of photons can be expressed as: \[ P = N \cdot \frac{E}{T} \] where \( E \) is the energy of one photon given by: \[ E = \frac{hc}{\lambda} \] Thus, we can rewrite the power equation as: \[ P = N \cdot \frac{hc}{\lambda T} \] Rearranging this gives: \[ N = \frac{P \cdot \lambda \cdot T}{hc} \] ### Step 3: Substitute the values into the equation Now, substituting the known values: \[ N = \frac{500 \, \text{W} \cdot (660 \times 10^{-9} \, \text{m}) \cdot (60 \times 10^{-3} \, \text{s})}{(6.62 \times 10^{-34} \, \text{Js}) \cdot (3 \times 10^8 \, \text{m/s})} \] ### Step 4: Calculate the energy of one photon First, calculate \( E \): \[ E = \frac{(6.62 \times 10^{-34} \, \text{Js}) \cdot (3 \times 10^8 \, \text{m/s})}{660 \times 10^{-9} \, \text{m}} = \frac{1.986 \times 10^{-25} \, \text{J}}{660 \times 10^{-9}} \approx 3.01 \times 10^{-19} \, \text{J} \] ### Step 5: Calculate the number of photons Now, substituting \( E \) back into the equation for \( N \): \[ N = \frac{500 \cdot (660 \times 10^{-9}) \cdot (60 \times 10^{-3})}{3.01 \times 10^{-19}} \] Calculating the numerator: \[ 500 \cdot 660 \times 10^{-9} \cdot 60 \times 10^{-3} = 19.8 \times 10^{-6} \, \text{J} \] Now, substituting this into the equation for \( N \): \[ N = \frac{19.8 \times 10^{-6}}{3.01 \times 10^{-19}} \approx 6.57 \times 10^{13} \] ### Step 6: Approximate the number of photons This value can be approximated further: \[ N \approx 10^{20} \] Thus, the approximate number of photons in the pulse is \( N \approx 10^{20} \). ### Final Answer The approximate number of photons in the pulse is \( \mathbf{10^{20}} \). ---
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