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If for hydrogen C(P) - C(V) = m and for ...

If for hydrogen `C_(P) - C_(V) = m` and for nitrogen `C_(P) - C_(V) = n`, where `C_(P)` and `C_(V)` refer to specific heats per unit mass respectively at constant pressure and constant volume, the relation between `m` and `n` is (molecular weight of hydrogen = 2 and molecular weight or nitrogen = 14)

A

m = 14n

B

n = 7n

C

m = 9n

D

n = 16n

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the relationship between the specific heats at constant pressure (C_P) and constant volume (C_V) for hydrogen and nitrogen. ### Step 1: Understand the relationship We know that for any gas, the difference between the specific heats at constant pressure and constant volume is given by: \[ C_P - C_V = R \] where \( R \) is the gas constant. However, in this problem, we are given that: - For hydrogen, \( C_P - C_V = m \) - For nitrogen, \( C_P - C_V = n \) ### Step 2: Use the molecular weights The molecular weight of hydrogen (H₂) is given as 2, and for nitrogen (N₂), it is given as 14. The specific heat capacities can be expressed in terms of the molecular weights: - For hydrogen, we can denote the specific heat capacities as \( C_{P,H} \) and \( C_{V,H} \). - For nitrogen, we denote them as \( C_{P,N} \) and \( C_{V,N} \). ### Step 3: Relate m and n From the problem, we have: \[ m = C_{P,H} - C_{V,H} \] \[ n = C_{P,N} - C_{V,N} \] ### Step 4: Express the specific heats using molecular weights The specific heats at constant volume for ideal gases can be related to their molecular weights: \[ C_V \propto \frac{1}{M} \] where \( M \) is the molecular weight. Therefore, we can express: - For hydrogen: \[ C_{V,H} = k \cdot \frac{1}{2} \] - For nitrogen: \[ C_{V,N} = k \cdot \frac{1}{14} \] ### Step 5: Calculate the difference for both gases Using the relationship \( C_P - C_V = R \) and substituting for \( C_V \): - For hydrogen: \[ m = C_{P,H} - C_{V,H} = C_{P,H} - k \cdot \frac{1}{2} \] - For nitrogen: \[ n = C_{P,N} - C_{V,N} = C_{P,N} - k \cdot \frac{1}{14} \] ### Step 6: Find the ratio of m to n To find the relationship between \( m \) and \( n \): \[ \frac{m}{n} = \frac{C_{P,H} - k \cdot \frac{1}{2}}{C_{P,N} - k \cdot \frac{1}{14}} \] ### Step 7: Simplify the ratio Assuming that the specific heats at constant pressure are proportional to the molecular weights, we can simplify: \[ \frac{m}{n} = \frac{14}{2} = 7 \] ### Conclusion Thus, the relationship between \( m \) and \( n \) is: \[ m = 7n \]
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