Home
Class 12
PHYSICS
A positively charged ball hangs from a s...

A positively charged ball hangs from a silk thread. We put a positive test carge `q_(0)` at a point and measure `F//q_(0)`,m then it can be prediccted that the electric field strength E.

A

`gt (E)/(q_(0))`

B

` lt (F)/(q_(0))`

C

`=(F)/(q_(0))`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Similar Questions

Explore conceptually related problems

A positively charged ball hangs from a long silk thread. Electric filed at a certain point (at the same horizontal level of ball) due to this charge is E. Let us put a positive test charge q_(0) at this point and measure F//q_(0) on this charges. then E

A positively charged ball hangs from a long silk thread. Electric filed at a certain point (at the same horizontal level of ball) due to this charge is E. Let us put a positive test charge q_(0) at this point and measure F//q_(0) on this charges. then E

A positively charged ring is in y - z plane with its centre at origin . A positive test charge q_(e ) , held at origin is released along x axis, then its speed

A positive point charge is placed at P in front of an earthed metal sheet S.Q and R are two points between P and S as shown in the diagram. If the electric field strength at Q and r are respectively E_(Q) and E_(R) , which one of the following statement is // are false?

Two point charges q and –q are at positions (0,0,d) and (0,0, –d) respectively . What is the electric field at (a,0,0 ) ?

Two point charges q and –q are at positions (0,0,d) and (0,0, –d) respectively . What is the electric field at (a,0,0 ) ?

Two point charges a and b whose magnitude are same, positioned at a certain distance along the positive x-axis from each other a is at origin. Graph is drawn between electrical field strength and distance x from a. E is taken positive if it is along the line joining from a to b From the graph it can be decided that

Two point charges q AND 2q are placed at (a,0) and (0,a) A point charge q^(1) is placed at a P on the quarter circle of radius a as shown in the diagram so that the electric field at the origin becomes zero

In a certain region of space, there exists a uniform and constant electric field of strength E along x-axis and uniform constant magnetic field of induction B along z-axis. A charge particle having charge q and mass m is projected with speed v parallel to x-axis from a point (a, b, 0). When the particle reaches a point( 2a, b//2 , 0) its speed becomes 2v. Find the value of electric field strength in term of m, v and co-ordinates.

A positively charged particle, having charge q, is accelerated by a potential difference V. This particle moving along the x-axis enters a region where an electric field E exists. The direction of the electric field is along positive y-axis. The electric field exists in the region bounded by the lines x=0 and x=a. Beyond the line x=a (i.e., in the region xgta ), there exists a magnetic field of strength B, directed along the positive y-axis. Find a. at which point does the particle meet the line x=a . b. the pitch of the helix formed after the particle enters the region xgea. (Mass of the particle is m.)