Benzene diazonium chloride on boiling with dilute sulphuric acid, gives

Options

A. Toluene
B. Benzoic acid
C. Benzene
D. Phenol

Answer

To solve the question regarding the reaction of benzene diazonium chloride with dilute sulfuric acid, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The main reactant is benzene diazonium chloride, which has the formula \( C_6H_5N_2Cl \).

2. **Understand the Reaction Conditions**:
- The reaction occurs when benzene diazonium chloride is boiled with dilute sulfuric acid (H₂SO₄).

3. **Reaction Mechanism**:
- When benzene diazonium chloride is treated with dilute sulfuric acid, it undergoes hydrolysis. The diazonium group (\( N_2^+ \)) is replaced by a hydroxyl group (\( -OH \)).
- The reaction can be summarized as follows:
\[ C_6H_5N_2Cl + H_2O \rightarrow C_6H_5OH + N_2 + HCl \]

4. **Identify the Main Product**:
- The main product of this reaction is phenol (\( C_6H_5OH \)).
- The side products formed during this reaction are nitrogen gas (\( N_2 \)) and hydrochloric acid (\( HCl \)).

5. **Conclusion**:
- Therefore, the product formed when benzene diazonium chloride is boiled with dilute sulfuric acid is phenol.

### Final Answer:
The product is **phenol**.

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