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Two particles move at right angle to each other. Their de Broglie wavelenghts are `lambda_(1)` and `lambda_(2)` respectively. The particles suffer perfectly inelastic collision. The de Broglie wavelenght `lambda`, of the final particle, is given by:

A

`lambda = ( lambda_(1) lambda_(2))/( sqrt( lambda_(1)^(2) + lambda_(2)^(2)))`

B

`lambda= sqrt( lambda_(1)lambda_(2))`

C

`lambda = sqrt( lambda_(1) + lambda_(2))`

D

`lambda= (lambda_(1)+lambda_(2))/(2)`

Text Solution

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The correct Answer is:
A
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