`TlI_(3)` is an ionic compound. In the aqueous solution it provides -

Options

A. `Tl^(+)` and `I_(3)^(-)`
B. `Tl^(3+)` and `I^(-)`
C. `Tl^(+) , I^(-) ` and `I_(2)`
D. `Tl^(+), I^(-) ` and `I_(2)`

Answer

To determine the ions provided by TlI₃ in aqueous solution, we need to analyze its dissociation.

### Step-by-Step Solution:

1. **Identify the Compound**: The compound in question is thallium(I) iodide, TlI₃.

2. **Dissociation in Aqueous Solution**: When TlI₃ is dissolved in water, it dissociates into its constituent ions. The dissociation can be represented as:
\[ \text{TlI}_3 \rightarrow \text{Tl}^+ + \text{I}_3^- \]
Here, TlI₃ breaks down into one thallium ion (Tl⁺) and one triiodide ion (I₃⁻).

3. **Understanding Oxidation States**: Thallium can exhibit two oxidation states: +1 and +3. However, in this case, TlI₃ specifically dissociates to form Tl⁺ (indicating the +1 oxidation state) and I₃⁻.

4. **Reason for the +1 State**: The preference for the +1 oxidation state over the +3 can be attributed to the inert pair effect. As we move down the group in the periodic table, the lower oxidation state (in this case, +1) becomes more stable due to the poor shielding effect of the d-electrons in heavier elements like thallium.

5. **Conclusion**: Therefore, in aqueous solution, TlI₃ provides the ions Tl⁺ and I₃⁻.

### Final Answer:
The ions provided by TlI₃ in aqueous solution are:
- Tl⁺ (thallium ion)
- I₃⁻ (triiodide ion)

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