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The number of four-digit numbers formed ...

The number of four-digit numbers formed by using the digits 0,2,4,5 and which are not divisible by 5, is

A

10

B

8

C

6

D

4

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of finding the number of four-digit numbers formed using the digits 0, 2, 4, and 5 that are not divisible by 5, we can follow these steps: ### Step 1: Identify the digits and conditions The available digits are 0, 2, 4, and 5. A four-digit number cannot start with 0. Additionally, since we want the number to be not divisible by 5, the last digit cannot be 0 or 5. ### Step 2: Determine the last digit Since the number must not be divisible by 5, the last digit can only be 2 or 4. Thus, we have 2 choices for the last digit. ### Step 3: Determine the first digit The first digit of a four-digit number cannot be 0. If the last digit is 2, the available digits for the first digit are 0 (not allowed), 4, and 5. If the last digit is 4, the available digits for the first digit are 0 (not allowed), 2, and 5. Therefore, in both cases, we have 2 choices for the first digit (either 2 or 5 if the last digit is 4, and either 4 or 5 if the last digit is 2). ### Step 4: Determine the second and third digits After choosing the first digit and the last digit, we will have 2 digits already used. We can use any of the remaining digits (including 0) for the second and third positions. Since we have 4 digits total and 2 digits have already been used, we have 2 remaining digits to choose from for the second digit, and then 1 remaining digit for the third digit. ### Step 5: Calculate the total combinations Now, we can calculate the total number of combinations: - For each choice of the last digit (2 choices: 2 or 4), - For each choice of the first digit (2 choices), - For the second digit (2 choices), - For the third digit (1 choice). Thus, the total number of four-digit numbers is calculated as follows: \[ \text{Total combinations} = (\text{choices for last digit}) \times (\text{choices for first digit}) \times (\text{choices for second digit}) \times (\text{choices for third digit}) \] \[ = 2 \times 2 \times 2 \times 1 = 8 \] ### Final Answer The total number of four-digit numbers formed by using the digits 0, 2, 4, and 5 that are not divisible by 5 is **8**. ---
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