Propene on reaction with hypochlorous acid gives ?

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Answer

To determine the product formed when propene reacts with hypochlorous acid, we can follow these steps:

### Step 1: Identify the Reactants
- **Propene**: The chemical formula for propene is \( \text{C}_3\text{H}_6 \), which can be represented as \( \text{CH}_3\text{CH}=\text{CH}_2 \).
- **Hypochlorous Acid**: The chemical formula for hypochlorous acid is \( \text{HOCl} \).

### Step 2: Understand the Reaction Mechanism
- The reaction of propene with hypochlorous acid will follow **Markovnikov's Rule**. This rule states that when HX (where X is a halogen or similar group) adds to an alkene, the hydrogen atom (H) will attach to the carbon with the greater number of hydrogen atoms, while the halogen (or OH group in this case) will attach to the carbon with fewer hydrogen atoms.

### Step 3: Analyze the Double Bond in Propene
- In propene, the double bond is between the first and second carbon atoms:
- **C1**: \( \text{CH}_3 \) (attached to 2 hydrogens)
- **C2**: \( \text{CH} \) (attached to 1 hydrogen)
- **C3**: \( \text{CH}_2 \) (attached to 2 hydrogens)

According to Markovnikov's Rule, the negative part of hypochlorous acid (the hydroxyl group, -OH) will attach to the carbon with fewer hydrogens, which is C2.

### Step 4: Determine the Product
- The positive part of hypochlorous acid (the chlorine, Cl) will attach to the carbon with more hydrogens, which is C1.
- Therefore, the product formed will be:
\[ \text{CH}_3\text{C(OH)}\text{CH}_2\text{Cl} \]
- This can also be written as:
\[ \text{CH}_3\text{CH(OH)}\text{CH}_2\text{Cl} \]

### Step 5: Final Product Representation
- The final product of the reaction between propene and hypochlorous acid is:
\[ \text{2-chloropropan-1-ol} \]