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Match list I with List II and select the...

Match list I with List II and select the correct answer using the codes given below
`{:(,"List I",,"List II"),(, "(types of ore )",,"(example)"),(P,"Oxide ore ",A.,"Feldspar"),(Q,"Sulphide ore ",B.,"Barytes "),(R,"sulphate ore ",C.,"Fluorspar"),(S,"Halide ore ",D.,"Galena"),(,,E.,"Corundum"):}`

A

P-B,Q-D,R-C,S-A

B

P-B,Q-D,R-E,S-A

C

P-E,Q-B,R-D,S-C

D

P-E,Q-D,R-B,S-C

Text Solution

AI Generated Solution

The correct Answer is:
To solve the matching question between List I (types of ore) and List II (examples), we will analyze each type of ore and find its corresponding example. ### Step-by-Step Solution: 1. **Identify Types of Ore:** - P: Oxide ore - Q: Sulphide ore - R: Sulphate ore - S: Halide ore 2. **Identify Examples:** - A: Feldspar - B: Barytes - C: Fluorspar - D: Galena - E: Corundum 3. **Match Each Type of Ore with Its Example:** - **Oxide Ore (P):** - Corundum (E) is an oxide mineral (Al2O3). - Therefore, P matches with E. - **Sulphide Ore (Q):** - Galena (D) is a well-known sulphide ore (PbS). - Therefore, Q matches with D. - **Sulphate Ore (R):** - Barytes (B) is barium sulfate (BaSO4). - Therefore, R matches with B. - **Halide Ore (S):** - Fluorspar (C) is calcium fluoride (CaF2), which is a halide mineral. - Therefore, S matches with C. 4. **Final Matching:** - P → E (Oxide ore → Corundum) - Q → D (Sulphide ore → Galena) - R → B (Sulphate ore → Barytes) - S → C (Halide ore → Fluorspar) ### Summary of Matches: - P (Oxide ore) → E (Corundum) - Q (Sulphide ore) → D (Galena) - R (Sulphate ore) → B (Barytes) - S (Halide ore) → C (Fluorspar) ### Conclusion: The correct matching is: - P - E - Q - D - R - B - S - C
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