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1 mol each of AgNO3, CuSO4 and AICI3 is...

`1` mol each of ` AgNO_3, CuSO_4` and `AICI_3` is electrolyzed. The number of faradays required is in the ration of:

A

`1 : 1 : 1`

B

`1 : 2 : 3`

C

`3 : 2 : 1`

D

`1 : 3 : 1`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find out how many Faradays are required for the electrolysis of each of the given compounds: AgNO3, CuSO4, and AlCl3. We will analyze each compound step by step. ### Step 1: Electrolysis of AgNO3 - The electrolysis of silver nitrate (AgNO3) can be represented as: \[ \text{AgNO}_3 \rightarrow \text{Ag}^+ + \text{NO}_3^- \] - During electrolysis, silver ions (Ag⁺) gain one electron (e⁻) to form solid silver (Ag): \[ \text{Ag}^+ + e^- \rightarrow \text{Ag} \] - Since 1 mole of Ag⁺ requires 1 mole of electrons, the number of Faradays required for AgNO3 is: \[ 1 \text{ Faraday} \] ### Step 2: Electrolysis of CuSO4 - The electrolysis of copper sulfate (CuSO4) can be represented as: \[ \text{CuSO}_4 \rightarrow \text{Cu}^{2+} + \text{SO}_4^{2-} \] - During electrolysis, copper ions (Cu²⁺) gain two electrons to form solid copper (Cu): \[ \text{Cu}^{2+} + 2e^- \rightarrow \text{Cu} \] - Since 1 mole of Cu²⁺ requires 2 moles of electrons, the number of Faradays required for CuSO4 is: \[ 2 \text{ Faradays} \] ### Step 3: Electrolysis of AlCl3 - The electrolysis of aluminum chloride (AlCl3) can be represented as: \[ \text{AlCl}_3 \rightarrow \text{Al}^{3+} + 3\text{Cl}^- \] - During electrolysis, aluminum ions (Al³⁺) gain three electrons to form solid aluminum (Al): \[ \text{Al}^{3+} + 3e^- \rightarrow \text{Al} \] - Since 1 mole of Al³⁺ requires 3 moles of electrons, the number of Faradays required for AlCl3 is: \[ 3 \text{ Faradays} \] ### Step 4: Finding the Ratio Now that we have the number of Faradays required for each compound, we can express them in ratio form: - For AgNO3: 1 Faraday - For CuSO4: 2 Faradays - For AlCl3: 3 Faradays Thus, the ratio of Faradays required for the electrolysis of AgNO3, CuSO4, and AlCl3 is: \[ 1 : 2 : 3 \] ### Final Answer The number of Faradays required is in the ratio of **1 : 2 : 3**. ---
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