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How many compounds are less basic than a...

How many compounds are less basic than aniline.

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The structure of saccharin is given as follows: How many following compounds are more basic than saccharin? .

Assertion : Acetanilide is less basic than aniline . Reason : Acetanilide is formed by reaction of aniline with acetic anhydride .

The lone pair of amines makes them basic. They react with acids to form acid-base salts. Amines are more basic than alcohols, ethers and water. When an amine is dissolved in water, an equilibrium is established , where water acts as an acid and transfer a proton to the amine. The basic strength of an amine can be measured by basicity constant K_(b) . Arylamines are less basic than alkylamines because the lone pair of nitrogen is delocalised with the aromatic ring and are less available for donation. Substituted arylamines can be either more basic or less basic than aniline , depending on the substituted . ERG substituents, such as -CH_(3), -NH_(2) and -OCH_(3) increases the basicity and EWG substituents , such as -Cl, -NO_(2) and -CN decreases basicity. While sp^(2)- hybridized nitrogen atom in pyridine is less basic then the sp^(3) -hybridized nitrogen in an alkylamine. The most basic carbanion is :

The lone pair of amines makes them basic. They react with acids to form acid-base salts. Amines are more basic than alcohols, ethers and water. When an amine is dissolved in water, an equilibrium is established , where water acts as an acid and transfer a proton to the amine. The basic strength of an amine can be measured by basicity constant K_(b) . Arylamines are less basic than alkylamines because the lone pair of nitrogen is delocalised with the aromatic ring and are less available for donation. Substituted arylamines can be either more basic or less basic than aniline , depending on the substituted . ERG substituents, such as -CH_(3), -NH_(2) and -OCH_(3) increases the basicity and EWG substituents , such as -Cl, -NO_(2) and -CN decreases basicity. While sp^(2)- hybridized nitrogen atom in pyridine is less basic then the sp^(3) -hybridized nitrogen in an alkylamine. pK_(b) order of the following compound is : (I) NH_(2)OH" "(II) NH_(2)NH_(2)" "(III) NH_(3)" "(IV)H_(2)O

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Why is methylamine more basic than aniline?

Methyl amine is........basic than aniline.

The pK_a value of (I) is less than the pK_a value to (II). Nonaromatic compounds are more stable than anti-aromatic compounds.