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Strontium crystallizes in a fcc unit cel...

Strontium crystallizes in a fcc unit cell with edge length a. it contains 0.2% Frenkel defect and another crystal of Sr contains 0.1% Schottky defect. Density of solid with Frenkel defect=`d_(f)` and density with Schottky defect=`d_(S)`, then

A

`d_(f)=d_(S)`

B

`d_(f) gt d_(S)`

C

`d_(f) lt d_(S)`

D

`d_(f)=2d_(S)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the effects of Frenkel and Schottky defects on the density of strontium crystals. ### Step-by-Step Solution: 1. **Understanding the Unit Cell and Density**: - Strontium crystallizes in a face-centered cubic (FCC) structure. In an FCC unit cell, there are 4 formula units of the substance per unit cell. - The density (\(d\)) of a crystal can be calculated using the formula: \[ d = \frac{Z \cdot M}{N_A \cdot a^3} \] where \(Z\) is the number of formula units per unit cell, \(M\) is the molar mass, \(N_A\) is Avogadro's number, and \(a\) is the edge length of the unit cell. 2. **Frenkel Defect**: - In a Frenkel defect, smaller cations move to interstitial sites, but no atoms leave the crystal lattice. Thus, the mass of the crystal remains the same. - Therefore, the density of the crystal with a Frenkel defect (\(d_f\)) remains unchanged: \[ d_f = \frac{Z \cdot M}{N_A \cdot a^3} \] 3. **Schottky Defect**: - In a Schottky defect, equal numbers of cations and anions leave the lattice, which decreases the total mass of the crystal. - If \(x\) is the fraction of the total number of cations and anions that leave the lattice, the effective number of formula units in the unit cell decreases. - For a Schottky defect with 0.1% defect, the new effective number of formula units (\(Z_s\)) can be calculated as: \[ Z_s = Z \cdot (1 - 0.001) = 4 \cdot 0.999 = 3.996 \] - The density of the crystal with a Schottky defect (\(d_s\)) is: \[ d_s = \frac{Z_s \cdot M}{N_A \cdot a^3} = \frac{3.996 \cdot M}{N_A \cdot a^3} \] 4. **Comparing Densities**: - Since \(d_f\) remains the same and \(d_s\) is reduced due to the loss of mass: \[ d_f > d_s \] - Therefore, the density of the crystal with a Frenkel defect is greater than that with a Schottky defect. ### Conclusion: The relationship between the densities is: \[ d_f > d_s \]
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