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The rate of change of torque 'tau' with ...

The rate of change of torque `'tau'` with deflection `theta` is maximum for a magnet suspended freely in a uniform magnetic field of induction `B` when `theta` is equal to

A

(a)`theta = 0^(@)`

B

(b)`theta = 45^(@)`

C

(c)`theta = 60^(@)`

D

(d)`theta = 90^(@)`

Text Solution

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The correct Answer is:
To solve the problem, we need to determine the angle `theta` at which the rate of change of torque `tau` with respect to deflection `theta` is maximum for a magnet suspended in a uniform magnetic field of induction `B`. ### Step-by-Step Solution: 1. **Understand the Torque Equation**: The torque (`tau`) experienced by a magnetic moment (`M`) in a magnetic field (`B`) is given by the equation: \[ \tau = M \cdot B \cdot \sin(\theta) \] where `theta` is the angle between the magnetic moment and the magnetic field. 2. **Differentiate Torque with Respect to Theta**: To find the rate of change of torque with respect to deflection, we need to differentiate `tau` with respect to `theta`: \[ \frac{d\tau}{d\theta} = M \cdot B \cdot \frac{d}{d\theta}(\sin(\theta)) \] Using the derivative of sine, we have: \[ \frac{d\tau}{d\theta} = M \cdot B \cdot \cos(\theta) \] 3. **Maximize the Rate of Change**: We want to find the value of `theta` that maximizes this derivative. The expression for the rate of change of torque is: \[ \frac{d\tau}{d\theta} = M \cdot B \cdot \cos(\theta) \] The maximum value of `\cos(\theta)` occurs when `\cos(\theta) = 1`. 4. **Determine the Angle**: The cosine function reaches its maximum value of 1 at: \[ \theta = 0^\circ \] 5. **Conclusion**: Therefore, the rate of change of torque with respect to deflection is maximum when: \[ \theta = 0^\circ \] ### Final Answer: The angle `theta` at which the rate of change of torque is maximum is: \[ \theta = 0^\circ \]
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