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Compound (P) forms a precipitate with Ag...

Compound (P) forms a precipitate with `AgNO_(3)`. The precipitate dissolves in excess reagent (P). (P) cannot be:

A

KOH

B

KCN

C

`Na_(2)S_(2)O_(3)`

D

`NH_(3)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze each of the compounds given as options to determine which one cannot be compound (P) based on the information provided. ### Step-by-Step Solution: 1. **Understanding the Problem**: - Compound (P) forms a precipitate with AgNO₃. - The precipitate dissolves in excess of the same reagent (P). - We need to find out which compound cannot be (P). 2. **Analyzing Each Option**: - **Option 1: KOH (Potassium Hydroxide)** - Reaction: AgNO₃ + KOH → Ag₂O (black precipitate) + KNO₃ + H₂O. - When excess KOH is added, Ag₂O does not dissolve. - Conclusion: KOH cannot be (P) since the precipitate does not dissolve in excess KOH. - **Option 2: KCN (Potassium Cyanide)** - Reaction: AgNO₃ + KCN → AgCN (white precipitate) + KNO₃. - When excess KCN is added, AgCN dissolves to form [Ag(CN)₂]⁻ (soluble complex). - Conclusion: KCN can be (P) since the precipitate dissolves. - **Option 3: Na₂S₂O₃ (Sodium Thiosulfate)** - Reaction: AgNO₃ + Na₂S₂O₃ → Ag₂S₂O₃ (white precipitate) + NaNO₃. - When excess Na₂S₂O₃ is added, Ag₂S₂O₃ dissolves to form [Ag(S₂O₃)₂]³⁻ (soluble complex). - Conclusion: Na₂S₂O₃ can be (P) since the precipitate dissolves. - **Option 4: NH₃ (Ammonia)** - Reaction: AgNO₃ + NH₃ → Ag₂O (black precipitate) + NH₄NO₃. - When excess NH₃ is added, Ag₂O dissolves to form [Ag(NH₃)₂]⁺ (soluble complex). - Conclusion: NH₃ can be (P) since the precipitate dissolves. 3. **Final Conclusion**: - The only compound that does not allow the precipitate to dissolve in excess is KOH. Therefore, compound (P) cannot be KOH. ### Answer: Compound (P) cannot be KOH. ---
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