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Arrange priority of CIP sequence of give...

Arrange priority of CIP sequence of given groups in decreasing order -
(I) `OH`
(II) `COOH`
(III) `CHOHCH_(3)`
(IV) `CH_(2)OH`

A

I gt II gt III gt IV

B

IV gt III gt II gt I

C

II gt III gt IV gt I

D

IV gt I gt II gt III

Text Solution

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The correct Answer is:
To arrange the priority of the given groups according to the Cahn-Ingold-Prelog (CIP) priority rules, we will follow these steps: ### Step 1: Identify the Atoms in Each Group - **Group I (OH)**: Contains oxygen (O) and hydrogen (H). - **Group II (COOH)**: Contains carbon (C), oxygen (O), and hydrogen (H). - **Group III (CHOHCH₃)**: Contains carbon (C) and hydrogen (H) in a hydroxyl (OH) group. - **Group IV (CH₂OH)**: Contains carbon (C), hydrogen (H), and a hydroxyl (OH) group. ### Step 2: Determine Atomic Mass According to the CIP rules, we assign priority based on the atomic mass of the atoms directly attached to the chiral center: - Oxygen (O) has a higher atomic mass than carbon (C). - Therefore, any group containing oxygen will have a higher priority than those containing only carbon. ### Step 3: Assign Priority Based on Atomic Mass 1. **Group II (COOH)**: Contains oxygen, which has the highest atomic mass among the groups. 2. **Group I (OH)**: Contains oxygen, but only has one oxygen atom compared to COOH which has two. 3. **Group III (CHOHCH₃)**: Contains carbon and has a hydroxyl group, but the carbon is attached to two hydrogens and one hydroxyl group. 4. **Group IV (CH₂OH)**: Contains carbon and has a hydroxyl group, but the carbon is attached to two hydrogens. ### Step 4: Compare Remaining Groups Now we compare Group III (CHOHCH₃) and Group IV (CH₂OH): - Group III (CHOHCH₃) has a carbon that is attached to two different groups (hydroxyl and a methyl group). - Group IV (CH₂OH) has a carbon that is attached to two hydrogens and a hydroxyl group. Since Group III has more diversity in its substituents, it will have a higher priority than Group IV. ### Final Priority Order Based on the analysis: 1. **Group II (COOH)** - Highest priority 2. **Group I (OH)** 3. **Group III (CHOHCH₃)** 4. **Group IV (CH₂OH)** - Lowest priority Thus, the final order in decreasing priority is: **COOH > OH > CHOHCH₃ > CH₂OH**
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