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What is the product when C(6)H(5)CH(2)NH...

What is the product when `C_(6)H_(5)CH_(2)NH_(2)` reacts with `HNO_(3)`?

A

`C_(6)H_(5)-N-=N`

B

`C_(6)H_(5)-CH_(2)-overset(o+)N-=N`

C

`C_(6)H_(5)-CH_(2)-OH`

D

`C_(6)H_(5)-NH_(2)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding the reaction of `C_(6)H_(5)CH_(2)NH_(2)` (benzylamine) with `HNO_(2)` (nitrous acid), we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Reactants**: - The reactant is benzylamine, which has the structure `C6H5CH2NH2`. - The reagent is nitrous acid, `HNO2`. 2. **Understand the Reaction**: - Benzylamine contains an amino group (-NH2) that can react with nitrous acid to form a diazonium salt. - The reaction between an amine and nitrous acid typically leads to the formation of a diazonium compound. 3. **Formation of Diazonium Salt**: - When benzylamine reacts with nitrous acid, it forms benzyl diazonium chloride (`C6H5CH2N2^+Cl^-`). - This is an unstable intermediate that can decompose easily. 4. **Decomposition of Diazonium Salt**: - The diazonium salt is highly unstable and will decompose when treated with water. - During this decomposition, it will lose nitrogen gas (N2) and form an alcohol. 5. **Final Product**: - The final product of this reaction is benzyl alcohol (`C6H5CH2OH`). - The overall reaction can be summarized as: \[ C6H5CH2NH2 + HNO2 \rightarrow C6H5CH2N2^+Cl^- \rightarrow C6H5CH2OH + N2 \] ### Conclusion: The product formed when `C_(6)H_(5)CH_(2)NH_(2)` reacts with `HNO_(2)` is benzyl alcohol (`C6H5CH2OH`).
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