A man of 'A' bood group marries a woman of 'AB' bood group .Which types of progeny would indicate that man is heterozyguos?

Options

A. O
B. A
C. B
D. AB

Answer

To solve the question, we need to analyze the blood groups of the parents and the possible blood groups of their progeny.

### Step-by-Step Solution:

1. **Identify the Blood Groups of the Parents:**
- The man has blood group 'A'.
- The woman has blood group 'AB'.

2. **Determine the Genotypes:**
- The blood group 'A' can be either homozygous (AA) or heterozygous (AO).
- The blood group 'AB' is always heterozygous (IAIB).

3. **Possible Alleles from Each Parent:**
- The man (A) can pass on either the A allele (if he is homozygous) or the A or O allele (if he is heterozygous).
- The woman (AB) can pass on either the A allele or the B allele.

4. **Create a Punnett Square:**
- If the man is homozygous (AA):
- Possible combinations with the woman (AB) would be:
- AA (Blood group A)
- AB (Blood group AB)
- Progeny would only have blood groups A or AB.

- If the man is heterozygous (AO):
- Possible combinations with the woman (AB) would be:
- AA (Blood group A)
- AB (Blood group AB)
- AO (Blood group A)
- BO (Blood group B)
- Progeny could have blood groups A, AB, or B.

5. **Conclusion:**
- The presence of a child with blood group B in the progeny would indicate that the man is heterozygous (AO) because the B blood group can only arise if the man contributes the O allele.

### Final Answer:
The type of progeny that would indicate that the man is heterozygous is a child with blood group B.

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