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The gas obtained by roasting of sulphide...

The gas obtained by roasting of sulphide ore is reacted with acidified potassium dichromate. A green colored compound 'X' is formed. The compound X can be :

A

`SO_(2)`

B

`Cr_(2)(SO_4)_(3)`

C

`Cl_(2)`

D

`CrO_(2)Cl_(2)`

Text Solution

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The correct Answer is:
To solve the question, we need to identify the gas produced by roasting a sulfide ore and the resulting compound formed when this gas reacts with acidified potassium dichromate. ### Step-by-Step Solution: 1. **Understand Roasting of Sulfide Ore**: - Roasting is a process where a sulfide ore is heated in the presence of air. This process converts the sulfide into an oxide and releases sulfur dioxide (SO₂) gas. - For example, if we take zinc sulfide (ZnS) as the sulfide ore, the reaction would be: \[ 2 \text{ZnS} + 3 \text{O}_2 \rightarrow 2 \text{ZnO} + 2 \text{SO}_2 \] - Here, the gas produced is sulfur dioxide (SO₂). 2. **Reaction with Acidified Potassium Dichromate**: - The gas (SO₂) is then reacted with acidified potassium dichromate (K₂Cr₂O₇) in the presence of sulfuric acid (H₂SO₄). - The reaction can be represented as: \[ 3 \text{SO}_2 + K_2Cr_2O_7 + 4 \text{H}_2SO_4 \rightarrow 2 \text{Cr}_2(SO_4)_3 + K_2SO_4 + 4 \text{H}_2O \] - In this reaction, chromium in potassium dichromate is reduced from +6 oxidation state to +3 oxidation state, resulting in the formation of chromium(III) sulfate (Cr₂(SO₄)₃). 3. **Identify the Green Colored Compound**: - The compound formed, chromium(III) sulfate (Cr₂(SO₄)₃), is typically green in color. - Therefore, the green colored compound 'X' formed in this reaction is chromium(III) sulfate. ### Conclusion: The green colored compound 'X' formed by the reaction of sulfur dioxide with acidified potassium dichromate is **chromium(III) sulfate (Cr₂(SO₄)₃)**.
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