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Diborane reacts with ammonia to initiall...

Diborane reacts with ammonia to initially forms X which on further heating gives borazine X is

A

`BH_(3).NH_(3)`

B

`B_(2)H_(6).NH_(3)`

C

`B_(2)H_(6).2NH_(3)`

D

`NH_(3)BH_(3)NH_(3)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the reaction between diborane (B2H6) and ammonia (NH3) to determine the intermediate product X that leads to the formation of borazine upon further heating. ### Step-by-Step Solution: 1. **Identify the Reactants**: - The reactants in this reaction are diborane (B2H6) and ammonia (NH3). 2. **Understand the Reaction Conditions**: - The reaction occurs at low temperatures initially. This is crucial for determining the product formed. 3. **Determine the Initial Product (X)**: - When diborane reacts with ammonia at low temperatures, it forms a complex. The stoichiometry of the reaction indicates that 2 moles of ammonia are required for every mole of diborane. - Therefore, the initial product X can be represented as B2H6·2NH3 (a complex of diborane with two moles of ammonia). 4. **Heating the Product**: - Upon further heating of the complex B2H6·2NH3 at high temperatures (around 200°C), the product undergoes decomposition to form borazine (B3N3H6) and hydrogen gas (H2). 5. **Conclusion**: - The compound X formed from the reaction of diborane and ammonia is B2H6·2NH3. ### Final Answer: The correct answer for X is **B2H6·2NH3**.
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