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Six distinct numbers are chosen from the...

Six distinct numbers are chosen from the first 10 natural numbers. The probability that 6 is the third largest of those chosen number is

A

`2/7`

B

`5/21`

C

`10/63`

D

`16/63`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of finding the probability that 6 is the third largest number when choosing 6 distinct numbers from the first 10 natural numbers, we can follow these steps: ### Step 1: Determine the Total Number of Ways to Choose 6 Numbers The total number of ways to choose 6 distinct numbers from the first 10 natural numbers (1 to 10) is given by the combination formula: \[ \text{Total ways} = \binom{10}{6} \] Calculating this: \[ \binom{10}{6} = \frac{10!}{6!(10-6)!} = \frac{10 \times 9 \times 8 \times 7}{4 \times 3 \times 2 \times 1} = 210 \] ### Step 2: Define the Event Where 6 is the Third Largest Number For 6 to be the third largest number among the chosen 6 numbers, we need to select 2 numbers that are greater than 6 and 3 numbers that are less than 6. ### Step 3: Choose Numbers Greater than 6 The numbers greater than 6 from the set {1, 2, 3, 4, 5, 6, 7, 8, 9, 10} are {7, 8, 9, 10}. We need to choose 2 from these 4 numbers: \[ \text{Ways to choose 2 from } \{7, 8, 9, 10\} = \binom{4}{2} \] Calculating this: \[ \binom{4}{2} = \frac{4!}{2!(4-2)!} = \frac{4 \times 3}{2 \times 1} = 6 \] ### Step 4: Choose Numbers Less than 6 The numbers less than 6 from the set are {1, 2, 3, 4, 5}. We need to choose 3 from these 5 numbers: \[ \text{Ways to choose 3 from } \{1, 2, 3, 4, 5\} = \binom{5}{3} \] Calculating this: \[ \binom{5}{3} = \frac{5!}{3!(5-3)!} = \frac{5 \times 4}{2 \times 1} = 10 \] ### Step 5: Calculate the Number of Favorable Outcomes Now, we can find the total number of favorable outcomes where 6 is the third largest number: \[ \text{Favorable outcomes} = \binom{4}{2} \times \binom{5}{3} = 6 \times 10 = 60 \] ### Step 6: Calculate the Probability Finally, the probability that 6 is the third largest number is given by the ratio of the number of favorable outcomes to the total outcomes: \[ \text{Probability} = \frac{\text{Favorable outcomes}}{\text{Total outcomes}} = \frac{60}{210} \] Simplifying this fraction: \[ \frac{60}{210} = \frac{2}{7} \] ### Final Answer Thus, the probability that 6 is the third largest number among the chosen numbers is: \[ \boxed{\frac{2}{7}} \]
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