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The total volume of dry gaseous products...

The total volume of dry gaseous products at STP, when 3 moles of electrons are transferred from anode to cathode in the electrolysis of water is `:`
( Volume of gas a STP =22.4L )

A

67.2L

B

50.4L

C

44.8L

D

56.0L

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of determining the total volume of dry gaseous products at STP when 3 moles of electrons are transferred during the electrolysis of water, we can follow these steps: ### Step 1: Understand the Electrolysis of Water In the electrolysis of water, water (H₂O) is split into hydrogen (H₂) and oxygen (O₂) gases. The reactions occurring at the electrodes are: - At the anode (oxidation): \[ 2H_2O \rightarrow O_2 + 4H^+ + 4e^- \] - At the cathode (reduction): \[ 2H_2O + 2e^- \rightarrow H_2 + 2OH^- \] ### Step 2: Determine Moles of Gases Produced From the reactions: - To produce 1 mole of O₂, 4 moles of electrons are needed. - To produce 1 mole of H₂, 2 moles of electrons are needed. ### Step 3: Calculate Moles of Oxygen Produced Given that 3 moles of electrons are transferred: - The moles of O₂ produced can be calculated as follows: \[ \text{Moles of O₂} = \frac{3 \text{ moles of electrons}}{4 \text{ moles of electrons per mole of O₂}} = 0.75 \text{ moles of O₂} \] ### Step 4: Calculate Moles of Hydrogen Produced - The moles of H₂ produced can be calculated as follows: \[ \text{Moles of H₂} = \frac{3 \text{ moles of electrons}}{2 \text{ moles of electrons per mole of H₂}} = 1.5 \text{ moles of H₂} \] ### Step 5: Convert Moles to Volume at STP Using the molar volume of a gas at STP (22.4 L/mol): - Volume of O₂ produced: \[ \text{Volume of O₂} = 0.75 \text{ moles} \times 22.4 \text{ L/mol} = 16.8 \text{ L} \] - Volume of H₂ produced: \[ \text{Volume of H₂} = 1.5 \text{ moles} \times 22.4 \text{ L/mol} = 33.6 \text{ L} \] ### Step 6: Calculate Total Volume of Gases Now, we can find the total volume of the gases produced: \[ \text{Total Volume} = \text{Volume of O₂} + \text{Volume of H₂} = 16.8 \text{ L} + 33.6 \text{ L} = 50.4 \text{ L} \] ### Final Answer The total volume of dry gaseous products at STP when 3 moles of electrons are transferred is **50.4 liters**. ---
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