The IUPAC name `C_(6)H_(5)-underset(C_(6)H_(5))underset(|)(C)H-CH_(2)-C Cl_(3)` is

Options

A. 1,1,1-trichloro -3,3- diphenyl propane
B. 1,1-diphenyl -3,3,3-trichloropropane
C. Both A and B
D. None of these

Answer

To determine the IUPAC name of the compound represented by the formula `C_(6)H_(5)-C(C)(C)H-CH_(2)-CCl_(3)`, we will follow these steps:

### Step 1: Identify the Structure
The compound consists of two phenyl groups (C6H5) attached to a carbon chain. There is also a carbon atom with three chlorine atoms (CCl3) attached to it.

### Step 2: Number the Carbon Chain
We need to number the carbon chain to identify the positions of the substituents. We can start numbering from either end, but we will choose the direction that gives the lowest numbers to the substituents.

1. Starting from the left (phenyl ring side):
- C1: Phenyl group
- C2: CH (attached to the phenyl)
- C3: CH2
- C4: C (with three Cl substituents)

2. Starting from the right (CCl3 side):
- C1: CCl3
- C2: CH2
- C3: CH (attached to the phenyl)
- C4: Phenyl group

### Step 3: Determine the Lowest Sum Rule
- If we number from the left, we get:
- C1 (phenyl), C2 (CH), C3 (CH2), C4 (C with Cl3)
- Sum = 1 + 2 + 3 + 4 = 10

- If we number from the right, we get:
- C1 (CCl3), C2 (CH2), C3 (CH), C4 (phenyl)
- Sum = 1 + 2 + 3 + 4 = 10

Since both numbering methods yield the same sum, we can proceed with either direction. However, we will choose the left side for naming.

### Step 4: Identify Substituents and Their Positions
- The substituents are:
- Two phenyl groups at C1 and C4
- A trichloro group at C4

### Step 5: Write the IUPAC Name
Using the information gathered:
- The compound has two phenyl groups, which we denote as "diphenyl."
- The trichloro substituent is at C4.
- The main carbon chain has a total of four carbons, hence it is a propane derivative.

Putting it all together, we write the name as:
**1,1,1-trichloro-3,3-diphenylpropane**

### Final Answer
The IUPAC name of the compound is **1,1,1-trichloro-3,3-diphenylpropane**.

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