`XeF_(6)` on complete hydrolysis gives

Options

A. `XeOF_(2)`
B. `XeO_(2)`
C. `XeO_(3)`
D. none of these

Answer

To determine the products formed from the complete hydrolysis of \( \text{XeF}_6 \), we can follow these steps:

### Step 1: Understand the Hydrolysis Process
Hydrolysis involves the reaction of a compound with water. In this case, we are looking at the hydrolysis of xenon hexafluoride (\( \text{XeF}_6 \)).

**Hint:** Remember that hydrolysis can be complete or partial, depending on the amount of water present.

### Step 2: Identify the Complete Hydrolysis Reaction
When \( \text{XeF}_6 \) undergoes complete hydrolysis, it reacts with an excess of water. The reaction can be represented as follows:

\[ \text{XeF}_6 + 6 \text{H}_2\text{O} \rightarrow \text{XeO}_3 + 6 \text{HF} \]

**Hint:** Look for the products formed when all the fluoride ions are replaced by hydroxyl groups from water.

### Step 3: Write the Products
From the reaction, we can see that the products of the complete hydrolysis of \( \text{XeF}_6 \) are:
- Xenon trioxide (\( \text{XeO}_3 \))
- Hydrofluoric acid (\( \text{HF} \))

**Hint:** Focus on the stoichiometry of the reaction to ensure you account for all atoms involved.

### Step 4: Conclusion
Thus, the final answer to the question is that the complete hydrolysis of \( \text{XeF}_6 \) gives \( \text{XeO}_3 \) and \( 6 \text{HF} \).

**Final Answer:** \( \text{XeO}_3 + 6 \text{HF} \)

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