`CH_3MgBr + CO_(2)overset("Dry ether")(rarr)Y overset(H_3O^(o+))(rarr)Z`
Identify Z from the following.

Options

A. Ethyl acetate
B. Acetic acid
C. Propanoic acid
D. Methyl acetate

Answer

To identify compound Z in the reaction CH₃MgBr + CO₂ → Y → Z, we can follow these steps:

### Step 1: Understand the Reactants
- The reactants are CH₃MgBr (a Grignard reagent) and CO₂ (carbon dioxide).
- Grignard reagents are highly reactive organomagnesium compounds that can react with electrophiles.

### Step 2: Reaction of Grignard Reagent with CO₂
- When CH₃MgBr reacts with CO₂ in dry ether, the nucleophilic carbon (C) of the Grignard reagent attacks the electrophilic carbon of CO₂.
- This results in the formation of a carboxylate intermediate.

### Step 3: Formation of Intermediate Y
- The reaction can be represented as follows:
\[ \text{CH}_3\text{MgBr} + \text{CO}_2 \rightarrow \text{CH}_3\text{C(=O)O}^-\text{MgBr}^+ \]
- The product Y is a magnesium carboxylate, specifically CH₃C(=O)O⁻MgBr⁺.

### Step 4: Hydrolysis of Intermediate Y
- When Y is treated with an acid (H₃O⁺), hydrolysis occurs, converting the carboxylate into a carboxylic acid.
- The reaction can be represented as:
\[ \text{CH}_3\text{C(=O)O}^-\text{MgBr}^+ + \text{H}_3\text{O}^+ \rightarrow \text{CH}_3\text{C(=O)OH} + \text{MgBr}^+ \]

### Step 5: Identify Compound Z
- The product Z formed after hydrolysis is CH₃C(=O)OH, which is acetic acid (or ethanoic acid).

### Final Answer
- Therefore, the compound Z is **acetic acid (CH₃COOH)**.