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Pb^(2+), Cu^(2+), Zn^(2+) and Ni^(2+) io...

`Pb^(2+), Cu^(2+), Zn^(2+) and Ni^(2+)` ions are present in a given acidic solution. On passing hydrogen sulphide gas through this solution, the available precipitate will contain

A

PbS and NiS

B

PbS and CuS

C

CuS and ZnS

D

CuS and NiS

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of which precipitates will form when hydrogen sulfide (H₂S) gas is passed through an acidic solution containing Pb²⁺, Cu²⁺, Zn²⁺, and Ni²⁺ ions, we can follow these steps: ### Step 1: Understand the solubility of sulfides in acidic solutions In acidic solutions, certain metal sulfides are soluble while others are not. Specifically, we need to identify which of the metal ions will form insoluble sulfides when H₂S is introduced. ### Step 2: Identify the sulfides of the given metal ions - **Lead (Pb²⁺)**: Lead(II) sulfide (PbS) is insoluble in water and will precipitate. - **Copper (Cu²⁺)**: Copper(II) sulfide (CuS) is also insoluble in water and will precipitate. - **Zinc (Zn²⁺)**: Zinc sulfide (ZnS) is soluble in acidic solutions and will not precipitate. - **Nickel (Ni²⁺)**: Nickel(II) sulfide (NiS) is insoluble in water and will precipitate. ### Step 3: Determine the precipitates formed When H₂S is passed through the acidic solution: - Pb²⁺ will precipitate as PbS. - Cu²⁺ will precipitate as CuS. - Zn²⁺ will not precipitate as ZnS due to its solubility in acidic conditions. - Ni²⁺ will precipitate as NiS. ### Step 4: Conclusion The precipitates that will form in the solution when H₂S is passed through it are PbS and CuS. Therefore, the available precipitate will contain CuS and PbS. ### Final Answer The available precipitate will contain CuS and PbS. ---
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