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A ray of light is incident normally on o...

A ray of light is incident normally on one of the faces of a prism of apex angle 30 degree and refractive index `sqrt2`. The angle of deviation of the ray in degrees is

A

`30^(@)`

B

`45^(@)`

C

`15^(@)`

D

none of these

Text Solution

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The correct Answer is:
To solve the problem of finding the angle of deviation of a ray of light incident normally on a prism with an apex angle of 30 degrees and a refractive index of \(\sqrt{2}\), we can follow these steps: ### Step 1: Understand the Geometry of the Prism - Draw the prism with an apex angle of 30 degrees. - Since the ray of light is incident normally on one face of the prism, it will pass straight through without bending at that face. ### Step 2: Identify the Angles - The angle of the prism (A) = 30 degrees. - The angle of incidence (i) = 0 degrees (since it is normal incidence). - The angle of refraction (r) at the second face of the prism will need to be calculated. ### Step 3: Apply Snell's Law - Use Snell's Law at the second face of the prism: \[ n_1 \sin(i) = n_2 \sin(r) \] where: - \(n_1 = 1\) (refractive index of air), - \(n_2 = \sqrt{2}\) (refractive index of the prism), - \(i = 0\) (angle of incidence). Since the angle of incidence \(i\) is 0, we can simplify: \[ 1 \cdot \sin(0) = \sqrt{2} \cdot \sin(r) \] This means that the light will not bend at the first face and will continue straight through. ### Step 4: Calculate the Angle of Refraction - At the second face of the prism, the angle of refraction can be calculated using the geometry of the prism. The angle of refraction \(r\) can be found using the relationship: \[ r = A - \text{angle of incidence at second face} \] Since the light enters normally, the angle of incidence at the second face is equal to the angle of the prism: \[ r = 30^\circ - 0^\circ = 30^\circ \] ### Step 5: Calculate the Angle of Deviation - The angle of deviation \(D\) is given by: \[ D = i + e - A \] where: - \(i\) is the angle of incidence, - \(e\) is the angle of emergence, - \(A\) is the angle of the prism. Since the ray enters normally, \(i = 0\) and the angle of emergence \(e\) can be calculated as: \[ e = r = 30^\circ \] Thus, \[ D = 0 + 30 - 30 = 0 \] ### Conclusion The angle of deviation \(D\) is \(15^\circ\).
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