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Gem dihalides on treatment with alcoholi...

Gem dihalides on treatment with alcoholic KOH give

A

Alkyne

B

Alkene

C

Alkane

D

All of these

Text Solution

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The correct Answer is:
To solve the question regarding the reaction of gem dihalides with alcoholic KOH, we can follow these steps: ### Step-by-Step Solution: 1. **Identify Gem Dihalides**: - Geminal dihalides (gem dihalides) are compounds that have two halogen atoms attached to the same carbon atom. An example is CH3CHBr2. 2. **Understand the Reaction**: - When gem dihalides are treated with alcoholic KOH, they undergo a reaction known as dehydrohalogenation. This reaction involves the elimination of hydrogen halides (HX), where X is the halogen. 3. **Write the Reaction**: - For the example CH3CHBr2, when treated with alcoholic KOH, the reaction can be represented as: \[ CH3CHBr2 + KOH \xrightarrow{alcoholic} CH \equiv C - H + 2HBr \] - Here, the two bromine atoms are eliminated along with two hydrogen atoms from adjacent carbons, leading to the formation of an alkyne. 4. **Identify the Product**: - The product formed from the reaction is an alkyne. In this case, the product is acetylene (ethyne), represented as CH≡CH. 5. **Conclusion**: - Therefore, the answer to the question is that gem dihalides on treatment with alcoholic KOH give an alkyne. ### Final Answer: Gem dihalides on treatment with alcoholic KOH give an alkyne. ---
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