2-Methylbutan-2-ol can be obtained by the acid catalyzed hydration of

Options

A. `CH_(3)CH_(2)CH = CH_(2)`
B. `CH_(3)CH=CHCH_(3)`
C. `(CH_3)_(2)C = CHCH_(3)`
D. Either of the three

Answer

To solve the question regarding the synthesis of 2-Methylbutan-2-ol through acid-catalyzed hydration, we will follow these steps:

### Step-by-Step Solution:

1. **Identify the Target Compound**:
We need to synthesize 2-Methylbutan-2-ol, which has the structure:
\[ \text{CH}_3\text{C(OH)(CH}_3)\text{CH}_2\text{CH}_3 \]
This indicates that the compound is a tertiary alcohol.

2. **Understand Acid-Catalyzed Hydration**:
Acid-catalyzed hydration of alkenes involves the addition of water (H₂O) across the double bond of an alkene in the presence of an acid. This process typically leads to the formation of an alcohol.

3. **Analyze the Given Options**:
We need to determine which alkene, when subjected to acid-catalyzed hydration, will yield 2-Methylbutan-2-ol.

4. **Evaluate Each Option**:
- **Option A**: \( \text{CH}_3\text{CH}_2\text{C}=\text{CH}_2 \)
- This compound, upon hydration, would form a secondary alcohol, not our target tertiary alcohol.
- **Option B**: \( \text{CH}_3\text{C}=\text{CH}\text{CH}_3 \)
- This compound also leads to a secondary alcohol upon hydration, which is not the desired product.
- **Option C**: \( \text{CH}_3\text{C}=\text{C(CH}_3)\text{CH}_2\text{CH}_3 \)
- This compound is a more complex alkene. When it undergoes hydration, it can form a tertiary carbocation, which is stable and will lead to the formation of 2-Methylbutan-2-ol.

5. **Confirm the Mechanism**:
- The double bond in Option C will attack a proton from the acid, forming a tertiary carbocation.
- Water will then attack this carbocation, leading to the formation of 2-Methylbutan-2-ol.

6. **Conclusion**:
Based on the analysis, Option C is the correct answer, as it leads to the formation of the desired tertiary alcohol.

### Final Answer:
2-Methylbutan-2-ol can be obtained by the acid-catalyzed hydration of **Option C**.

---