Home
Class 12
CHEMISTRY
Molar conductivity of aqueous solution o...

Molar conductivity of aqueous solution of HA is 200 `Scm^2mol^(-1)` ,pH of this solution is 4. Calculate the value fo `Pk_a(HA)"at"25^(@)` C.
Given : `Lambda _M^oo(NaA)=100Scm^2mol^(-1)`,bidwedge _M^oo(HCl)=425Scm^2mol^(-1)`,
`Lambda_M^oo(NaCl)=125Scm^2mol^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
4
Promotional Banner

Similar Questions

Explore conceptually related problems

Molar conductivity of aqueous solution of HA is 200Scm^(2)mol^(-1),pH of this solution is 4 Calculate the value of pK_(a)(HA) at 25^(@)C . Given ^^_(M)^(oo)(NaA)=100scm^(2)mol^(-1), ^^_(M)^(oo)(HCl)=425Scm^(2)mol^(-1), ^^_(M)^(oo)(NaCl)=125 Scm^(2)mol^(-1)

Molar conductivity of aqueous solution of HA is 200Scm^(2)mol^(-1),pH of this solution is 4 Calculate the value of pK_(a)(HA) at 25^(@)C . Given ^^_(M)^(oo)(NaA)=100scm^(2)mol^(-1), ^^_(M)^(oo)(HCl)=425Scm^(2)mol^(-1), ^^_(M)^(oo)(NaCl)=125 Scm^(2)mol^(-1)

Molar conductivity of a solution of an electrolyte AB_3 is 150 Scm^2mol^(-1) . If it ionises as AB_(3)toA^(3+)+3B^(-) , its equivalent conductivity will be :

The molar conductivity of 0.25 mol L^(-1) methanoic acid is 46.1 S cm^(2) mol^(-1) . Calculate the degree of dissociation constant. Given : lambda_((H^(o+)))^(@)=349.6S cm^(2)mol^(-1) and lambda_(HCOO^(-))^(@)=54.6Scm^(2)mol^(-1)

The molar conductivity of a 1.5 M solution of an electrolyte is found to be 138.9 S cm^(2) mol^(-1) . Calculate the conductivity of this solution.

The molar conductivity of a 1.5 M solution of an electrolyte is found to be 138.9 S cm^(2) mol^(-1) . Calculate the conductivity of this solution.

Calculate degree of dissociation of 0.02 M acetic acid at 298 K given that mho_(m)(CH_(3)COOH)=17.37 cm^(2) mol^(-1),lambda_(m)^(@)(H+)=345.8 S cm^(2) mol^(-1), lambda_(m)^(@)(CH_(3)COO^(-))=40.2 Scm^(2) mol^(-1)

Molar conductance of 1M solution of weak acid HA is 20 ohm^(-1) cm^(2) mol^(-1) . Find % dissocation of HA: (^^_(m)^(o)(H^(+)) =350 S cm^(2) mol^(-1)),(^^_(m)^(o)(A^(-)) =50 S cm^(2) mol^(-1))

We have taken a saturated solution of AgBr , whose K_(sp) is 12xx10^(-14). If 10^(-7)M of AgNO_(3) are added to 1L of this solutino, find the conductivity ( specific conductance ) of the solution in terms of 10^(-7)S m^(-1) units. Given : lambda^(@)._((Ag^(o+)))=6xx10^(-3)S m^(2) mol^(-1) lambda^(@)._((Br^(c-)))=8xx10^(-3)S m^(2)mol^(-1) lambda^(@)._((NO_(3)^(C-)))=7XX10^(-3)S m^(2) mol^(-1)

Calculate the value of equivalent conductivity of MgCl_(2) at infinite dilution if lambda^(oo)(Mg^(2+))= 106.12 "ohm"^(-1)cm^(-2)"mol"^(-1), lambda^(oo)(Cl^(-))=76.34"ohm"^(-1)cm^(2)"mol"^(-1) .