The compound fromed when Ethyl bromide is heated with dry silver oxide is

Options

A. dimethylether
B. diethylether
C. methylalcohol
D. ethylalcohol

Answer

To solve the question regarding the compound formed when ethyl bromide is heated with dry silver oxide, we can follow these steps:

### Step-by-Step Solution

1. **Identify the Reactants**:
- The reactant is ethyl bromide, which has the chemical formula \( \text{C}_2\text{H}_5\text{Br} \) or \( \text{CH}_3\text{CH}_2\text{Br} \).
- The other reactant is dry silver oxide, represented as \( \text{Ag}_2\text{O} \).

2. **Understand the Reaction Type**:
- When alkyl halides (like ethyl bromide) react with dry silver oxide, they typically undergo a reaction that leads to the formation of ethers. This is known as the ether formation reaction.

3. **Write the General Reaction**:
- The general reaction can be represented as:
\[ 2 \text{RBr} + \text{Ag}_2\text{O} \rightarrow \text{R-O-R} + 2 \text{AgBr} \]
- Here, \( \text{R} \) represents the ethyl group \( \text{C}_2\text{H}_5 \).

4. **Substitute the Ethyl Group**:
- For our specific case, substituting \( \text{R} \) with \( \text{C}_2\text{H}_5 \):
\[ 2 \text{C}_2\text{H}_5\text{Br} + \text{Ag}_2\text{O} \rightarrow \text{C}_2\text{H}_5\text{-O-C}_2\text{H}_5 + 2 \text{AgBr} \]

5. **Identify the Product**:
- The product formed is \( \text{C}_2\text{H}_5\text{-O-C}_2\text{H}_5 \), which is known as diethyl ether.

6. **Conclusion**:
- Therefore, the compound formed when ethyl bromide is heated with dry silver oxide is **diethyl ether**.

### Final Answer:
The compound formed is **diethyl ether** (Option B).