When NaCl is heated with sulphuric acid in the presence of `MnO_(2)` a greenish-yellow gas is liberated. The gas is

Options

A. `Cl_(2)`
B. `NH_(3)`
C. `N_(2)`
D. `H_2`

Answer

To solve the question, we need to analyze the reaction that occurs when sodium chloride (NaCl) is heated with sulfuric acid (H₂SO₄) in the presence of manganese dioxide (MnO₂).

### Step-by-Step Solution:

1. **Identify the Reactants**: The reactants in this reaction are sodium chloride (NaCl) and sulfuric acid (H₂SO₄). Manganese dioxide (MnO₂) is used as a catalyst.

2. **Write the Reaction**: The reaction can be represented as:
\[ \text{NaCl} + \text{H}_2\text{SO}_4 + \text{MnO}_2 \rightarrow \text{MnCl}_2 + \text{NaHSO}_4 + \text{H}_2\text{O} + \text{Cl}_2 \]

3. **Balance the Reaction**: To balance the equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation. The balanced equation is:
\[ 4 \text{NaCl} + 1 \text{MnO}_2 + 4 \text{H}_2\text{SO}_4 \rightarrow 1 \text{MnCl}_2 + 4 \text{NaHSO}_4 + 2 \text{H}_2\text{O} + 2 \text{Cl}_2 \]

4. **Identify the Products**: From the balanced equation, we can see that one of the products formed is chlorine gas (Cl₂).

5. **Color of the Gas**: The problem states that a greenish-yellow gas is liberated. Chlorine gas (Cl₂) is known to have a greenish-yellow color.

6. **Conclusion**: Therefore, the gas that is liberated when NaCl is heated with sulfuric acid in the presence of MnO₂ is chlorine gas (Cl₂).

### Final Answer:
The greenish-yellow gas liberated is **Cl₂ (Chlorine gas)**.

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