Phenyl magnesium bromide reacts with methanol to give :-

Options

A. A mixture of anisol and `Mg (OH)Br`
B. A mixture of benzene and `Mg(Ome)Br`
C. A mixture of toluene and `Mg(OH)Br`
D. A mixture of Phenol and `Mg(Me)Br`

Answer

To solve the question regarding the reaction of phenyl magnesium bromide with methanol, we can follow these steps:

### Step 1: Identify the Reactants
- **Phenyl Magnesium Bromide (C6H5MgBr)**: This is a Grignard reagent where the phenyl group (C6H5) is bonded to magnesium bromide.
- **Methanol (CH3OH)**: This is a simple alcohol.

### Step 2: Understand the Reaction Mechanism
- Grignard reagents are nucleophiles and can react with electrophiles. In this case, methanol has a hydroxyl group (-OH) which can act as an electrophile.

### Step 3: Nucleophilic Attack
- The phenyl group (C6H5) from phenyl magnesium bromide will attack the hydrogen atom of the hydroxyl group in methanol. This is because the hydrogen atom is slightly positive due to the electronegativity of oxygen.

### Step 4: Formation of Products
- When the phenyl group attacks the hydrogen, it forms a bond, and the electrons from the O-H bond shift towards the oxygen atom, creating an alkoxide ion (C6H5O^-).
- The magnesium bromide part (MgBr) will associate with the alkoxide ion to form phenyl magnesium alkoxide (C6H5OMgBr).

### Step 5: Protonation
- The alkoxide ion (C6H5O^-) can then be protonated by another molecule of methanol, resulting in the formation of anisole (C6H5OCH3) and magnesium bromide hydroxide (Mg(OH)Br).

### Final Products
- The final products of the reaction are:
- Anisole (C6H5OCH3)
- Magnesium bromide (MgBr) associated with the hydroxide ion (OH^-).

### Conclusion
The reaction of phenyl magnesium bromide with methanol produces anisole and magnesium bromide hydroxide.