When dry silver chloride is fused with sodium carbonate, we get pure :

Options

A. Silver
B. Chlorine
C. Sodium
D. Carbomonoxide

Answer

To solve the question, we need to analyze the reaction between dry silver chloride (AgCl) and sodium carbonate (Na2CO3).

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactants are dry silver chloride (AgCl) and sodium carbonate (Na2CO3).

2. **Write the Chemical Reaction**:
- When these two compounds react, the general reaction can be represented as:
\[ 2 \text{AgCl} + \text{Na}_2\text{CO}_3 \rightarrow 2 \text{Ag} + 2 \text{NaCl} + \text{CO}_2 + \text{O}_2 \]
- This equation shows that two moles of silver chloride react with one mole of sodium carbonate to produce two moles of silver, two moles of sodium chloride, one mole of carbon dioxide, and one mole of oxygen.

3. **Analyze the Products**:
- From the balanced equation, we can see that the products formed are:
- Silver (Ag)
- Sodium chloride (NaCl)
- Carbon dioxide (CO2)
- Oxygen (O2)

4. **Determine the Pure Product**:
- The question specifically asks for the pure substance obtained from the reaction. The only pure element produced in this reaction is silver (Ag).

5. **Conclusion**:
- Therefore, when dry silver chloride is fused with sodium carbonate, the pure substance obtained is **silver**.

### Final Answer:
When dry silver chloride is fused with sodium carbonate, we get pure **silver**.

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