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If the frequency of a recessive allele i...

If the frequency of a recessive allele is 0.4. What will be the frequency of individuals with dominant phenotype in the population?

A

0.68

B

0.6

C

0.84

D

0.36

Text Solution

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The correct Answer is:
To solve the problem of finding the frequency of individuals with a dominant phenotype in a population where the frequency of a recessive allele is given as 0.4, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Allele Frequencies**: - Let the frequency of the recessive allele (q) = 0.4. - Since the total frequency of alleles in a population must equal 1, we can find the frequency of the dominant allele (p): \[ p + q = 1 \] \[ p = 1 - q = 1 - 0.4 = 0.6 \] 2. **Use the Hardy-Weinberg Principle**: - According to the Hardy-Weinberg equilibrium, the frequencies of genotypes can be expressed as: \[ p^2 + 2pq + q^2 = 1 \] - Here, \( p^2 \) represents the frequency of homozygous dominant individuals, \( 2pq \) represents the frequency of heterozygous individuals, and \( q^2 \) represents the frequency of homozygous recessive individuals. 3. **Calculate the Frequency of Dominant Phenotype**: - The dominant phenotype includes both homozygous dominant and heterozygous individuals. Therefore, we need to calculate \( p^2 + 2pq \): - First, calculate \( p^2 \): \[ p^2 = (0.6)^2 = 0.36 \] - Next, calculate \( 2pq \): \[ 2pq = 2 \times 0.6 \times 0.4 = 0.48 \] - Now, add these two values to find the total frequency of the dominant phenotype: \[ \text{Dominant Phenotype Frequency} = p^2 + 2pq = 0.36 + 0.48 = 0.84 \] 4. **Conclusion**: - The frequency of individuals with the dominant phenotype in the population is **0.84**. ### Final Answer: The frequency of individuals with the dominant phenotype is **0.84**.
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