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"40 ml "(N)/(10)HCl solution is mixed wi...

`"40 ml "(N)/(10)HCl` solution is mixed with 60 ml of `(N)/(20)KOH` solution. The resulting mixture will be

A

Acidic

B

Basic

C

Neutral

D

Cannot be predicted

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to determine the resulting nature of the mixture when 40 mL of \( \frac{N}{10} \) HCl is mixed with 60 mL of \( \frac{N}{20} \) KOH. We will follow these steps: ### Step 1: Calculate the Normality of HCl and KOH - The normality of HCl is given as \( \frac{N}{10} \), which is equal to \( 0.1 \, N \). - The normality of KOH is given as \( \frac{N}{20} \), which is equal to \( 0.05 \, N \). ### Step 2: Calculate the Moles of HCl - Volume of HCl = 40 mL = \( 40 \times 10^{-3} \) L - Moles of HCl = Normality × Volume (in L) \[ \text{Moles of HCl} = 0.1 \, N \times 40 \times 10^{-3} \, L = 4 \times 10^{-3} \, \text{moles} \] ### Step 3: Calculate the Moles of KOH - Volume of KOH = 60 mL = \( 60 \times 10^{-3} \) L - Moles of KOH = Normality × Volume (in L) \[ \text{Moles of KOH} = 0.05 \, N \times 60 \times 10^{-3} \, L = 3 \times 10^{-3} \, \text{moles} \] ### Step 4: Determine the Reaction The reaction between HCl and KOH is a neutralization reaction: \[ \text{HCl} + \text{KOH} \rightarrow \text{KCl} + \text{H}_2\text{O} \] From the balanced equation, we see that 1 mole of HCl reacts with 1 mole of KOH. ### Step 5: Identify the Limiting and Excess Reagents - Moles of HCl = \( 4 \times 10^{-3} \) - Moles of KOH = \( 3 \times 10^{-3} \) Since KOH is the limiting reagent (as it will be completely consumed first), we can find out how much HCl will react with KOH. ### Step 6: Calculate the Moles of HCl Remaining - Moles of HCl that react with KOH = Moles of KOH = \( 3 \times 10^{-3} \) - Moles of HCl remaining = Initial moles of HCl - Moles of HCl that reacted \[ \text{Moles of HCl remaining} = 4 \times 10^{-3} - 3 \times 10^{-3} = 1 \times 10^{-3} \, \text{moles} \] ### Step 7: Determine the Nature of the Resulting Mixture Since there is leftover HCl in the solution, the resulting mixture will be acidic. ### Final Answer The resulting mixture will be **acidic**. ---
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