`k_(2)CO_(3)` cannot be prepared by solvay process because

Options

A. `K_(2)CO_(3)` is more soluble
B. `K_(2)CO_(3)` is less soluble
C. `KHCO_(3)` is more soluble than `NaHCO_(3)`
D. `KHCO_(3)` is less soluble than `NaHCO_(3)`

Answer

To understand why \( K_2CO_3 \) cannot be prepared by the Solvay process, we need to analyze the process itself and the solubility of the compounds involved.

### Step-by-Step Solution:

1. **Understanding the Solvay Process**:
- The Solvay process is primarily used to produce sodium carbonate (\( Na_2CO_3 \)) from sodium chloride (\( NaCl \)), ammonia (\( NH_3 \)), and water (\( H_2O \)).
- The key reaction in the Solvay process is:
\[ NaCl + NH_3 + H_2O + CO_2 \rightarrow NaHCO_3 \]
- Sodium bicarbonate (\( NaHCO_3 \)) precipitates out of the solution and can be heated to produce sodium carbonate.

2. **Considering Potassium Compounds**:
- If we attempt to use potassium chloride (\( KCl \)) instead of sodium chloride in the Solvay process, we would form potassium bicarbonate (\( KHCO_3 \)).
- The reaction would be similar:
\[ KCl + NH_3 + H_2O + CO_2 \rightarrow KHCO_3 \]

3. **Solubility of Potassium Bicarbonate**:
- The key issue arises with the solubility of potassium bicarbonate compared to sodium bicarbonate.
- Potassium bicarbonate (\( KHCO_3 \)) is more soluble in water than sodium bicarbonate (\( NaHCO_3 \)).
- This means that when \( KHCO_3 \) is formed, it does not precipitate out of the solution due to its higher solubility.

4. **Conclusion**:
- Since \( KHCO_3 \) remains dissolved in the solution and does not precipitate, we cannot isolate it as a solid product in the same way we can with \( NaHCO_3 \) in the Solvay process.
- Therefore, \( K_2CO_3 \) cannot be prepared by the Solvay process because potassium bicarbonate does not precipitate due to its higher solubility compared to sodium bicarbonate.

### Final Answer:
\( K_2CO_3 \) cannot be prepared by the Solvay process because potassium bicarbonate (\( KHCO_3 \)) is more soluble than sodium bicarbonate (\( NaHCO_3 \)), preventing its precipitation.