An alkene `(A)C_(16)H_(16)` on ozonolysis gives only one product `(B)(C_(8)H_(8)O)`. Compound (B) on reaction with `NH_(2)OH` followed by reaction with `H_(2)SO_(4), Delta` gives N - methyl benzamide the compound 'A' is -

Options

A.
B.
C.
D.

Answer

To determine the compound (A) from the given information, we will follow these steps:

### Step 1: Analyze the information given
We know that compound (A) is an alkene with the formula \(C_{16}H_{16}\). Upon ozonolysis, it yields compound (B) with the formula \(C_{8}H_{8}O\). Compound (B) further reacts with hydroxylamine (\(NH_2OH\)) and then with sulfuric acid (\(H_2SO_4\)) to produce N-methyl benzamide.

### Step 2: Calculate the degree of unsaturation for compound (B)
The degree of unsaturation (DU) can be calculated using the formula:
\[ DU = \frac{2C + 2 - H}{2} \]
For compound (B) \(C_{8}H_{8}O\):
- \(C = 8\)
- \(H = 8\)

Substituting the values:
\[ DU = \frac{2(8) + 2 - 8}{2} = \frac{16 + 2 - 8}{2} = \frac{10}{2} = 5 \]
This indicates that compound (B) has 5 degrees of unsaturation.

### Step 3: Identify the structure of compound (B)
Given that compound (B) has a degree of unsaturation of 5, it likely contains a benzene ring (which accounts for 1 degree of unsaturation) and additional double bonds. Since it has a total of 8 carbon atoms, we can assume that it has a structure that includes a benzene ring and additional carbon atoms with double bonds.

### Step 4: Determine the structure of compound (B)
The structure of compound (B) can be deduced as follows:
- The benzene ring contributes 6 carbons.
- The remaining 2 carbons can be connected through a double bond, leading to a structure like acetophenone (\(C_6H_5COCH_3\)).

### Step 5: Confirm the reaction to N-methyl benzamide
When compound (B) (assumed to be acetophenone) reacts with hydroxylamine, it forms an oxime. Upon heating with sulfuric acid, this oxime can rearrange to form N-methyl benzamide.

### Step 6: Determine the structure of compound (A)
Since compound (A) is an alkene that yields two equivalents of compound (B) upon ozonolysis, we can deduce that compound (A) must be a symmetrical alkene that can break down into two molecules of acetophenone. The likely structure for compound (A) is:
\[ \text{(C}_6\text{H}_5\text{)}_2\text{C}=\text{C}(\text{C}_6\text{H}_5) \]
This structure consists of two phenyl groups attached to a double bond.

### Final Answer
The compound (A) is:
\[ \text{1,2-Diphenylethylene (or stilbene)} \]

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